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September 26, 2025, 02:44:21 am

Author Topic: Related Rates/Tank problem  (Read 812 times)  Share 

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tcg93

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Related Rates/Tank problem
« on: October 20, 2010, 09:32:57 pm »
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Why is the answer C?
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Stormer

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Re: Related Rates/Tank problem
« Reply #1 on: October 20, 2010, 09:45:42 pm »
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dv/dt=2-kRootH
V=nr^2h

nr^2=2
V=2h

dv/dh = 2
dh/dv=1/2

dh/dt = dv/dt x dh/dv

=1/2 x 2-kRootH

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tcg93

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Re: Related Rates/Tank problem
« Reply #2 on: October 20, 2010, 10:46:17 pm »
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dv/dt=2-kRootH
V=nr^2h

nr^2=2
V=2h

dv/dh = 2
dh/dv=1/2

dh/dt = dv/dt x dh/dv

=1/2 x 2-kRootH



Why is dv/dt=2-kRootH ??

Isn't it only fresh water being poured in so you're meant to exclude that?
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mark_alec

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Re: Related Rates/Tank problem
« Reply #3 on: October 20, 2010, 11:21:51 pm »
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Isn't it only fresh water being poured in so you're meant to exclude that?
The salt is irrelevant for this question, as they just want to know the change in height with respect to time.

If they asked you to model the mass of salt as a function of time, it would be different.

Martoman

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Re: Related Rates/Tank problem
« Reply #4 on: October 20, 2010, 11:29:23 pm »
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yeah exactly my thoughts. Its a trick.
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