how could the results obtained be affected if:
a) the mixture in step 5 of the procedure were not tested with more barium chloride solution?
not all sulfate have been reacted and therefore the precipitate is understated.
b) the filtrate were not tested with silver nitrate solution when the precipitate was washed in step 8.
to rid of impurities from the solution so that the precipitate from the filter paper are rid of impurities.
Step 5:
boil the mixture for a further minute then remove it from the heat and allow the precipitate to settle. ensure no sulfate ions remain in the solution by adding several more drops of barium chloride solution.if more percipitate forms add 3ml of barium chloride solution and testfor unreatedsulfate ions.
step 8:
collect the last drops of filtrate in a 100 ml beaker and test for the presence of chloride ions by adding a few drops of silver nitrate solution to the filtrate. if solution becomes cloudy, wash the precipitate with a further 10ml of warm water and repeat the test
dont think my answer is not right and too brief. please help
