I feel like helping Respectful people in questions.

[Respect]

How do i solve these without a calculator, can someone show me pretty please.

[luffy]

Question 1:
Remember that the expansion of (you can find this using binomial expansion)
This same expansion applies, where a = 4x, and b = 3y.
Therefore,






Question 2:
For this question, I find it better to use an "estimated" trial and error approach.

You want the first x-term to have a power, such that the second term has the same, but negative power (so that they cancel each other out). You could simply try a few combinations, but you will find that it will be the 3rd term (i.e. when is raised to a power of 4, while the is squared -> this will result in x^12 terms as shown below).

Therefore,
The third term will be:










Hope I helped.

[Respect]

Question 1:
Remember that the expansion of (you can find this using binomial expansion)
This same expansion applies, where a = 4x, and b = 3y.
Therefore,






Question 2:
For this question, I find it better to use an "estimated" trial and error approach.

You want the first x-term to have a power, such that the second term has the same, but negative power (so that they cancel each other out). You could simply try a few combinations, but you will find that it will be the 3rd term (i.e. when is raised to a power of 4, while the is squared -> this will result in x^12 terms as shown below).

Therefore,
The third term will be:










Hope I helped.

actually dude, ur answer to qs one is correct, but thjeirs is incorrect, because if u notice they forgot to put the y^2

[luffy]

Question 1:
Remember that the expansion of (you can find this using binomial expansion)
This same expansion applies, where a = 4x, and b = 3y.
Therefore,






Question 2:
For this question, I find it better to use an "estimated" trial and error approach.

You want the first x-term to have a power, such that the second term has the same, but negative power (so that they cancel each other out). You could simply try a few combinations, but you will find that it will be the 3rd term (i.e. when is raised to a power of 4, while the is squared -> this will result in x^12 terms as shown below).

Therefore,
The third term will be:










Hope I helped.

actually dude, ur answer to qs one is correct, but thjeirs is incorrect, because if u notice they forgot to put the y^2

Oh, I didn't see that. Nice work on pointing that out.

[Respect]

Uhh these are really bugging me, i need to graph them labeling all asymptopes, and intercepts... can someone please show me how

[Water]

hey for your first equation

when you have e^|x-1| + 4


You split this into hybrid functions


Your first equation should be

 e^x-1 + 4 x> or equal to 1


Second Equation should be

e^1-x + 4    x < 1


Then you can plot it. The modulus rule should apply for the rest

[Respect]

hey for your first equation

when you have e^|x-1| + 4


You split this into hybrid functions


Your first equation should be

 e^x-1 + 4 x> or equal to 1


Second Equation should be

e^1-x + 4    x < 1


Then you can plot it. The modulus rule should apply for the rest

hmm somehow, either thats wrong, or i cant graph it the way its suppose to be ..mmhhhmm ..

[Water]

I think its the latter :x, keep trying ?

[Respect]

hey for your first equation

when you have e^|x-1| + 4


You split this into hybrid functions


Your first equation should be

 e^x-1 + 4 x> or equal to 1


Second Equation should be

e^1-x + 4    x < 1


Then you can plot it. The modulus rule should apply for the rest

ohh figured it out, thanks water ..  .


water... awkward lol