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May 01, 2026, 04:52:43 pm

Author Topic: Complex no.s - circles  (Read 1324 times)  Share 

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Greatness

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Complex no.s - circles
« on: April 11, 2011, 04:19:22 pm »
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How come the equation is translated 2 units right, but is translated 1 right and up??
Also how come there's a minus sign in the middle of this eqn ?

TrueTears

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Re: Complex no.s - circles
« Reply #1 on: April 11, 2011, 04:24:21 pm »
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a+bi, remember a represents the real ordinate and b represents the complex ordinate on the argand diagram. The geometric interpretation of |a-b|=x is that the point a and b are x units apart.

Use the same intuition here, it just means the complex number z is 2 units away from the complex number on the argand diagram.
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Re: Complex no.s - circles
« Reply #2 on: April 11, 2011, 04:52:28 pm »
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Im saahhhhh noob... -.- Can you explain it again but differently? LOL

luffy

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Re: Complex no.s - circles
« Reply #3 on: April 11, 2011, 05:28:15 pm »
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Instead of looking at it that way, view translations in a general sense.
Example:



let z = x + yi and (a + bi) is a complex constant.









You can see that the graph of has been translated 'a' units in the positive direction of the x-axis (i.e. right) and 'b' units in the positive direction of the y-axis (i.e. up).

So, in your question:

is translated unit right and units up from the equation .

Hope I helped.
« Last Edit: April 11, 2011, 05:32:48 pm by luffy »

Greatness

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Re: Complex no.s - circles
« Reply #4 on: April 11, 2011, 05:54:50 pm »
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 If i have |z-1| + |z+1| = 3
When i sub in z= x + iy and you get the modulus stuff, why is that we have to subtract one of the terms from each side, then do the squaring and expanding etc?

vea

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Re: Complex no.s - circles
« Reply #5 on: April 11, 2011, 05:59:10 pm »
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That just makes the whole squaring process easier so that after squaring with the perfect square rule, the middle term won't be two surds multiplied with each other.
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Re: Complex no.s - circles
« Reply #6 on: April 11, 2011, 06:40:00 pm »
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My brain is hatin maths today :(
So continuing from this question, |z-1| + |z+1| = 3
i eventually get to this stage:

Why is that we dont square the 3 and the root separately? I.e Why do we square the terms together as a whole?
HATIN MATHS.

pi

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Re: Complex no.s - circles
« Reply #7 on: April 11, 2011, 06:41:47 pm »
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Just butting in, but I like to think of these as loci. Saves me all the algebra :)



(check a GMA textbook if you need refreshing, then apply it here)

TrueTears

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Re: Complex no.s - circles
« Reply #8 on: April 11, 2011, 06:45:17 pm »
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My brain is hatin maths today :(
So continuing from this question, |z-1| + |z+1| = 3
i eventually get to this stage:

Why is that we dont square the 3 and the root separately? I.e Why do we square the terms together as a whole?
HATIN MATHS.
coz a^2+b^2 =/= (a+b)^2
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Re: Complex no.s - circles
« Reply #9 on: April 11, 2011, 08:44:32 pm »
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My brain is hatin maths today :(
So continuing from this question, |z-1| + |z+1| = 3
i eventually get to this stage:

Why is that we dont square the 3 and the root separately? I.e Why do we square the terms together as a whole?
HATIN MATHS.

Look at it this way:

2 + 4 = 6
Squaring both sides,
(2 + 4)^2 = 36

Expand both sides.

36 = 36

Doing it the other way:
2 + 4 = 6
2^2 + 4^4 does not equal 36.
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Re: Complex no.s - circles
« Reply #10 on: April 11, 2011, 08:50:05 pm »
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Hmmm okay lol, hopefully maths is more friendly towards me tomorrow :P Thanks!!