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June 14, 2024, 11:13:33 am
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Author Topic: Another Quick Question  (Read 1030 times)  Share 

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zibb3r

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Another Quick Question
« on: June 27, 2011, 11:26:29 pm »
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If f(x) = (2x-1)/(x^2 - 2x - 8)

Can you please explain why the graph is positive when f(x)>0

Thanks
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taiga

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Re: Another Quick Question
« Reply #1 on: June 28, 2011, 01:18:58 am »
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The graph is positive when f(x)> 0 because f(x) > 0
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tony3272

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Re: Another Quick Question
« Reply #2 on: June 28, 2011, 05:43:53 pm »
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Quote from: taiga on June 28, 2011, 01:18:58 am
The graph is positive when f(x)> 0 because f(x) > 0
Lol i love how teachers always tell us not to answer a question with the question  :P , but this is seriously the only way to explain this.

Quote from: zibb3r on June 27, 2011, 11:26:29 pm
If f(x) = (2x-1)/(x^2 - 2x - 8)

Can you please explain why the graph is positive when f(x)>0

Thanks
I'm not sure where you're getting confused with this, but basically if you view f(x) as the y axis on your graph then when f(x)>0 it will be above the x axis, hence it will have a positive value.
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cltf

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Re: Another Quick Question
« Reply #3 on: June 28, 2011, 07:20:23 pm »
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I think he meant f'(x).
Prove it by subbing in values?
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