Bio sac help please anyone

[sally baker]

Okay guys i have a sac due tomorrow i have not stated its on dihbybrid crosses . we did a dihbyrid cross of corn with four traits black smooth , black wrinkly and yellow smooth yellow wrinkly. we counted each of the four traits  of class total. Okay how do i work out the ratio for each and im confused has anyone done an experiment like this , in need of help

[sally baker]

Thanks alot for no one to reply . Just shows how much you guys are helping :/

[jadeee]

To do a dihybrid cross, or a cross of any kind, you'd need to know the genotypes of the parents, and that would involve assigning alleles for each trait.  (i.e. you'd need to know which allele was for the dominant phenotype and which allele was for the recessive..)

How many did you get for each trait?

[sally baker]

4

[Russ]

Thanks alot for no one to reply . Just shows how much you guys are helping :/

People don't exist to provide help for you on demand

[scar]

Number of Black wrinkly / total number of seeds counted      =  fraction of Black Wrinkly.
Number of Black smooth / total number                                 =  fraction of Black smooth.
etc, etc. for yellow wrinkly and yellow smooth.
Divide all your fractions by the smallest one and you get their ratio to each other.

With luck you should get a 9:3:3:1 ratio (assuming the genes for wrinkles and colour are on different chromosomes)

9  will be Both dominant traits.
3 will be 1 dominant and 1 recessive trait.
3 will be 1 recessive and 1 dominant trait.   (just the different trait from the other 3)
1 will be both traits in recessive form.