Assigning oxidation numbers

[Bhootnike]

C6 H12 06 + 6H2SO4--> 6C + 6H30+ +6HSO4-

Can someome please help me assign oxidation numbers to the above.
n.b, first compound is glucose, and the plus sign after h30 indicates hydronium ion, while - sign after hs04 indicates anion.

[LukeHigham]

Reactants: C = 0; H = +1; O = -2; S = +6.
Products: C = 0; H = +1; O = -2; S = +6.

Not a redox reaction.

Instead, a dehydration.

[Bhootnike]

could you please explain how you got those oxidation numbers?

[Starlight]

C6H1206=0

6(x) + 12(1) + 6(-2) = 0

therefore x= C= 0

For H2S04

2(1) + S + 4(-2) = 0

S - 6 = 0

S= 6

Same method for products

Here are some rules:


Elements - elemental elements = 0

Compounds:

Group 1 (I) = +1

Group 2 (II) = +2

Group 13 (III) = +3

Group 14 (IV) except C, Si = +4

Hydrogen = +1 with non- metals, -1 with metals

Fluorine = -1

Oxygen= -2 except with F, -1 in peroxides

The oxidation number of a monoatomic atom is the same as its charge, e.g. Na+ has oxidation number of +1

The sum of the oxidation numbers must be zero for a neutral molecule.

The sum of the oxidation numbers must be equal to the overall charge for a molecular ion such as SO42-