Author Topic: MTH1030 Assignment 02 question help (Read 2300 times) Tweet Share

blahh1234 · « **on:** October 09, 2013, 02:30:13 pm »

im currently doing mth1030 and i have an assignment due this week and i have no idea how to go about qu 3. any help would be greatly appreciated thanks!

TrueTears · « **Reply #1 on:** October 10, 2013, 01:05:02 am »

$\sum_{i=0}^n i^3 =\frac{n^2(n+1)^2}{4}= \frac{n^4}{4} + \frac{n^3}{2} + \frac{n^2}{4}$

$a = \frac{1}{4}, b = \frac{1}{2}, c = \frac{1}{4}, d=e=0$

I'll leave you to prove it using induction (very easy to do)

BigAl · « **Reply #2 on:** October 10, 2013, 09:03:31 am »

So they removed freaking apple logo question haha

blahh1234 · « **Reply #3 on:** October 10, 2013, 09:37:22 am »

Thanks!

kimk2kr · « **Reply #4 on:** October 10, 2013, 02:32:35 pm »

Quote from: TrueTears on October 10, 2013, 01:05:02 am

$\sum_{i=0}^n i^3 =\frac{n^2(n+1)^2}{4}= \frac{n^4}{4} + \frac{n^3}{2} + \frac{n^2}{4}$

$a = \frac{1}{4}, b = \frac{1}{2}, c = \frac{1}{4}, d=e=0$

I'll leave you to prove it using induction (very easy to do)

would you be able to explain this in tiny bit more detail please

tyty

Devva[R] · « **Reply #5 on:** October 10, 2013, 09:02:00 pm »

All you're doing is finding values for $a,b,c,d$ and $e$ that satisfy the equation

$<br />an^4+bn^3+cn^2+dn+e = 1^3+2^3+3^3+...+n^3<br />$

You have five unknowns so have to set up a system of five equations to solve for $a,b,c,d$ and $e$

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Author Topic: MTH1030 Assignment 02 question help (Read 2300 times) Tweet Share

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