recognition question help?

[Yoda]

given that the derivative of 5/2x^2-1 is -20x/(2x^2-10^2. Find the value of a given that integral (upper limit a, lower limit 1) of
(20x/(2x^2-1)^2 +1)dx =37/7.

[Avainer]

This is so hard to read, you should work on formating and use more brackets. In working and on forum. Assuming I read it right, you need to find integral(low 1 top a) of the second eqn given and put that as equal to 37/3. Then, the thing you put in the square brackets is the first equation given. You need up with [5/(2xs^2 -1)](low 1 top a) = 37/3 Then solve for a. Hope that was helpful.

[myanacondadont]

Can you not just;   
Put it in calc and solve for a? I got 1.356.

It sounds like an integration by recognition problem but I can't quite make it out so I just did that.

[keltingmeith]

Can you not just;   
Put it in calc and solve for a? I got 1.356.

It sounds like an integration by recognition problem but I can't quite make it out so I just did that.

VCAA will want an exact value - you've given a numerical value.
Not to mention if you need to show method or this is exam 1, you're in trouble. You should be able to do any question you see both with and without a calculator.

[Yoda]

Its tech free