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July 23, 2025, 01:23:23 am
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Author Topic: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)  (Read 32184 times)  Share 

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Mayesy

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Re: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)
« Reply #45 on: November 06, 2014, 10:35:02 pm »
Also, why is A for question 3d 4, I had 37e/25
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chuck981996

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Re: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)
« Reply #46 on: November 06, 2014, 10:48:02 pm »
Quote from: simondaaanng on November 06, 2014, 10:23:31 pm
Q4e. "Find the minimum value of n". Wouldn't it be n=14 instead of n>=14?

I think my answer's good too though - VCAA would accept either.
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jumcakes

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Re: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)
« Reply #47 on: November 06, 2014, 10:56:48 pm »
Quote from: Mayesy on November 06, 2014, 10:35:02 pm
Also, why is A for question 3d 4, I had 37e/25

Nearest integer :(
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Mayesy

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Re: 2014 Mathematical Methods Exam 2 Paper + ER Solutions
« Reply #48 on: November 06, 2014, 11:27:44 pm »
Quote from: Mayesy on November 06, 2014, 10:22:48 pm
Can someone please explain why question 9 in mc is A and not E?
Still waiting for an explanation anyone?
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NyaTaku

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Re: 2014 Mathematical Methods Exam 2 Paper + ER Solutions
« Reply #49 on: November 06, 2014, 11:30:03 pm »
Quote from: Mayesy on November 06, 2014, 11:27:44 pm
Still waiting for an explanation anyone?

Range of f(x) = Domain of f inverse.

ran f= (4,inf) therefore the domain of the inverse would be (4,inf)
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Mayesy

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Re: 2014 Mathematical Methods Exam 2 Paper + ER Solutions
« Reply #50 on: November 06, 2014, 11:54:29 pm »
Quote from: NyaTaku on November 06, 2014, 11:30:03 pm
Range of f(x) = Domain of f inverse.

ran f= (4,inf) therefore the domain of the inverse would be (4,inf)
Ahh right I forgot that it approaches 4 from above, and when I graphed it on my calculator is appeared to begin at 4, my mistake, thanks.
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hisoka

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Re: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)
« Reply #51 on: November 07, 2014, 07:02:43 pm »
Question 5.c.i, should be [1,3) since 0 isn't a positive number, and if it were translated 1 unit to the left, one of the intersections would be x=0.
Credits: Dr He and Big Garry Zhu
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keltingmeith

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Re: 2014 Mathematical Methods Exam 2 Paper + Solutions (MCQ + ER)
« Reply #52 on: November 07, 2014, 07:05:55 pm »
Quote from: hisoka on November 07, 2014, 07:02:43 pm
Question 5.c.i, should be [1,3) since 0 isn't a positive number, and if it were translated 1 unit to the left, one of the intersections would be x=0.
Credits: Dr He and Big Garry Zhu

This has been fixed, if you check the updated question 5 upload.
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