Author Topic: A DE (Read 1122 times) Tweet Share

/0 · « **on:** February 22, 2010, 12:05:59 am »

NVM IGNORE THIS ONE

*FACEPALM*&

$\dot{y}+0.1y = 0.1e^{-0.1t}$

When trying to find the particular solution, I chose $y_p = Ae^{-0.1t}$

$\dot{y}_p = -0.1Ae^{-0.1t}$

What happens when

$-0.1Ae^{-0.1t}+0.1Ae^{-0.1t}=0.1e^{-0.1t}$

$e^{-0.1t}=0$ ?

thx xD

Ahmad · « **Reply #1 on:** February 22, 2010, 12:08:10 am »

$y = Ae^{-0.1t}$ is a solution to the homogeneous equation, which means you should alter your ansatz to t multiplied by your initial guess, so $y_p = At\cdot e^{-0.1t}$ .

Search the forums now!

We have moved!

Author Topic: A DE (Read 1122 times) Tweet Share

/0

A DE

Ahmad

Re: A DE

Recent Posts

User:
Password: