Challenging Spesh Q

[samiira]

any help much appreciated   

[m@tty]

where ...

I have done basically none of the questions where you are asked to "solve" a differential, so I'm not sure if they want, for example:

for the first one

Or

   ??


Not too much help, I know. But the wording is really confusing me; I hope this helps you though, in some way. =]

[pooshwaltzer]

Extending Matty's response...

N=Ae^[(a-b)t]; A=e^(c2-c1)

When t=0, N=a

So ... a=Ae^[(a-b)0] ... A=a

N=ae^[(a-b)t]

Limitation = change in population is independent of time, ie. a constant, which may not be a realistic expectation and carries practical implications.

[samiira]

Thanks for that.. wud u know how to do this one

[m@tty]

And, splitting into partial fractions:
Let



;







I've got to go, but that seems correct so far.

[Martoman]

http://img812.imageshack.us/f/helpw.jpg/

That should walk you through all you need.

[samiira]

THANK YOUUUU!!!!!..