Happy's Chem practise exam 2010

[happyhappyland]

mmm but its not the same bonding... just because it has a bigger molar mass by 4.5 g/mol and the fact that the butanol will be able to form hydrogen bonds makes me inclined to defend my answer?

But isnt the chlorine more electronegative that the oxygen?... wait im not sure what im saying.
This question was on my sac, and I got it right with that answer. Im not sure if they accepted butanol aswell cos it was a very poor sac and many MC Qs had two answers.

[stonecold]

I think butan-1-ol also.  Both are polar I believe, but chlorowhatever can only make dipole-dipole bonds, whereas the alcohol can make hydrogen bonds which are stronger and require more energy to break...

[happyhappyland]

Just came across a mistake Question 5 c) SHOULD read

c.    A solution of bromine of unknown concentration is placed in a sample cell with a path length of 2 cm. Absorbance is at 0.48.


[Br2] = ________________ M

[azn_dj]

Not bad happyhappyland, but I think a lot of your questions are irrelevant for vce.
I have only looked at multi choice for now, but here is some of my feedback.
E.g. Question 3 - we arent expected to know about phenols, or paracetamol. If they were in the exam, there should be enough information.

I like question 6 - although if I wrote it, I wouldnt specify it as being a condenstaion polymer - but because people are drilled into the thought of polymers being addition polymers, this would be a great question.
7 - I dont like the "wrong" choices, I would have done something like 2,3,-Dicholoro-1-fluoro-1,4-dimethylbutane. Or even 3,5-dichloro-2-fluoro-5-methylpentane
Yeah you can probably see why I would put these as a choice.
8 - probably pointed out before that it can't be mls. BUT if you made the concentration ppm and then asked people to work out how many mls, then this would be a real trick. But I would have 80ml as one choice, 0.08ml (the real answer) as another choice.
9 - VCE students aren't required to know about aldehydes and Ketones, however if we are given an NMR or an IR of one, we should be able to draw the molecule without realizing its an aldehyde or a ketone. And if you were going to use pentone,why not make it trickier and say acetone?

[Mao]

9 - VCE students aren't required to know about aldehydes and Ketones, however if we are given an NMR or an IR of one, we should be able to draw the molecule without realizing its an aldehyde or a ketone. And if you were going to use pentone,why not make it trickier and say acetone?

Because acetone is propanone, and a ketone with 5 carbons is pentanone.