Probability Help

[user_5]

A die is weighted as follows:
Pr(2) = Pr(3) = Pr(4) = Pr(5) = 0.2
Pr(1) = Pr(6) = 0.1

The die is rolled twice, and the smaller of the numbers showing is noted. Let Y represent this value.

Find Pr(Y = 1)

[the.watchman]

Well I guess let's take the possibilities





So

On second thoughts, the probability is the same as getting a 1 on either roll:

[pooshwaltzer]

Pr(Y = 1) = 0.2 ... watchman, need to double your answer because 1 can be either on 1st roll or 2nd roll.

[the.watchman]

Pr(Y = 1) = 0.2 ... watchman, need to double your answer because 1 can be either on 1st roll or 2nd roll.

Oops, fixed

[user_5]

Oh okay, thanks the.watchman.
I eventually figured out the answer, similar to your first approach before checking back here.
The book has the answer 0.19, so I'm assuming in this case, the first approach is required?

[the.watchman]

Oh okay, thanks the.watchman.
I eventually figured out the answer, similar to your first approach before checking back here.
The book has the answer 0.19, so I'm assuming in this case, the first approach is required?

Damnit, I had to change my above answer AGAIN because I forgot something
It should be 0.19, not 0.2

[pooshwaltzer]

oh frak! not possible (1,1)...absence of coffee to blame...not gonna have any at this hour tho.