For the dissolution of silver chloride, technically the second equation refers to the formation of a silver-amine complex, not the dissolution of silver chloride. The mechanism is when amine is added, it removes some Ag+, thus driving the first equilibrium to the right, increasing Cl-. The solubility constant for AgCl will be maintained (Ag+ decreases and Cl- increases). The 'most' correct answer is A, though technically [AgCl] isn't a real quantity, and should be 1 and omitted from the equation.
For the second question, I don't see how A can work. An increased volume generally mean more salt can be dissolved, not an 'increase' in undissolved salt. Addition of Cl- might work for some cases, but generally when you have a low Ag+ concentration and there's little free Ag+, adding Cl- won't do much at all. (The competing equation with ammonia is quite strong, unless you add VERY concentrated NaCl, you won't really get the AgCl back.) I don't think any of the options are really correct.
For the third question, you can only assume that for weak acids because initially there's only water, no conjugate salts or H+ present. For most system however, you cannot assume the system is 'clean' initially, and there may be some products already present.