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June 17, 2024, 08:10:58 am
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Author Topic: Convert (-2)+ 2√3 i to polar form?  (Read 1768 times)  Share 

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chickenpop

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Convert (-2)+ 2√3 i to polar form?
« on: October 28, 2010, 05:10:11 pm »
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I keep on getting this wrong for some reason, think I'm missing something crucial 

I always get (-pi/3) as the angle, but it's actually 2pi/3. What am I doing wrong? :-\
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98.40_for_sure

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #1 on: October 28, 2010, 05:12:45 pm »
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Designate a reference angle and solve. Then according to quadrant, specify the actual angle
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InitialDRulz

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #2 on: October 28, 2010, 05:13:17 pm »
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well the negative 2 means its gonna be in the left hand side...

So yeah LOL
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superflya

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #3 on: October 28, 2010, 05:13:50 pm »
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graph it and see where the point lies, u subtract pi/3 from pi.
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vea

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #4 on: October 28, 2010, 05:14:06 pm »
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If you picture it, the point is in the 2nd quadrant (-2,2root3)

so tan(angle)=2root3/-2

=-root3

so angle=2pi/3 (because tan is negative in the 2nd quadrant)
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jasoN-

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #5 on: October 28, 2010, 05:14:47 pm »
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is in quadrant 2
ie.


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Yitzi_K

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #6 on: October 28, 2010, 05:15:39 pm »
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Since Re(z) is negative, and Im(z) is positive, the angle must be in the second quadrant, hence it's 2pi/3.
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chickenpop

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Re: Convert (-2)+ 2√3 i to polar form?
« Reply #7 on: October 28, 2010, 05:48:25 pm »
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Oh, I feel so silly lol :P Thanks everyone
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