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September 30, 2025, 01:41:57 am

Author Topic: Integration  (Read 1425 times)  Share 

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squance

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Integration
« on: May 02, 2008, 08:56:17 pm »
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Integrate the following:

sin^2(x) dx
(I got cos^3 (x)/3 - x + c as an answer but the answer says cos^3 (x)/ 3 - cos (x) + C. Why is it so??)

(x^4+1) loge(x^5+ 5x) dx
(I have no idea how to work this out!!!)

ice_blockie

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Re: Integration
« Reply #1 on: May 02, 2008, 09:08:45 pm »
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Part 2: You have to use the substitution method, which is the 'opposite' of a chain rule for differentiation.

i.e.



« Last Edit: May 02, 2008, 09:19:52 pm by ice_blockie »

squance

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Re: Integration
« Reply #2 on: May 02, 2008, 09:15:00 pm »
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Part 2: You have to use the substitution method.

Here's what i did:
(x^4+1) loge(x^5+ 5x) dx

let u = x^5 + 5x
du/dx = 5x^4 + 5
du/dx = 5(x^4+1)
du/5dx = x^4 + 1

integration....
du/5dx logeu dx
1/5logeu du

Then what next??? You can't integrate log, can you???

cara.mel

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Re: Integration
« Reply #3 on: May 02, 2008, 09:19:33 pm »
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You can use integration by parts I guess



Then all you have to do is differentiate log. (set it to the f(x) half, so f(x) = log(x^5+5x), g'(x) = (x^4+1)

Anyway I am no good at maths, I havent bothered to check if what I said would be helpful but that what I've been taught to do in case of PANIC, LOG
« Last Edit: May 02, 2008, 09:22:16 pm by caramel »

AppleXY

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Re: Integration
« Reply #4 on: May 02, 2008, 09:26:43 pm »
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For Part 1, you gotta use the trig identities

i.e. =
« Last Edit: May 02, 2008, 09:28:26 pm by AppleXY »

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ice_blockie

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Re: Integration
« Reply #5 on: May 02, 2008, 09:33:41 pm »
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Hey squance, is the answer to part 2

dcc

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Re: Integration
« Reply #6 on: May 02, 2008, 09:48:36 pm »
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Let






Now from here on, you have to experiment with a technique called 'integration by parts' (as caramel said), but a simple way of using this technique is to consider:







Therefore using this integral as above:







« Last Edit: May 03, 2008, 05:29:48 pm by dcc »