Can anyone please explain to me as to why sodium hydride is a base?
Because it is able to accept protons, especially from strong acids, hence it is a strong base.
Accept it to form NaH2+? Or what?
It is a strange (yet strong) base in that it is an ionic compound
If it reacts with water (water acts as an acid): NaH (s) + H2O (l) --> NaOH (aq) + H2 (g)
SO the reactions do not look like normal acid-base reactions
(NB, it can only accept protons from weak acids, not strong acids -I made the mistake in my above post)
The reaction is correct - the thing to note is that the "base" part is actually the H- part. H- + H+ --> H2. As you might expect, this makes it a very strong base. The Na+ is there as a counter ion to ensure neutrality of the compound (in the reaction, it is actually a spectator ion).
Similarly, with NaOH: OH- is the base part while Na+ is the counter-ion. In reaction, OH- + H+ --> H2O while Na+ is a spectator ion.
I don't reckon Unit 3 can be truly self taught in the way that, say, a maths subject can be. There are far fewer questions than in maths where you can get heaps and heaps of practise for each type of question. (That said, if your teacher isn't very good and doesn't provide many questions, that doesn't help much anyway.) You can certainly get a bit of a basis for it by yourself, but some concepts are notoriously confusing, and the problem with analytical techniques in Unit 3 is that there is so much junk to sift through. The other problem is you can think you understand a concept, but in fact you have part of it 'half-right'. I'm a bit biased because my chemistry teacher was so good so I really gained a lot by listening to her. I also find that VCE textbooks do not explain some concepts fantastically (eg. back-titration). I had already read Zumdahl's Chemical Principles before Yr 12. It is a great reference book which cleared up a lot of things for me.
Moderator action: removed real name, sorry for the inconvenience