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October 19, 2025, 08:23:50 pm
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Author Topic: STUCK ON MOTION T_T  (Read 679 times)  Share 

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DannyN

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STUCK ON MOTION T_T
« on: February 11, 2011, 10:26:55 pm »
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hey guys im completely lost with this question... can you guys help me ^^

In a road test, a car was uniformly accelerated from rest over a distance of 400m in 19.0s. The driver then applied the brakes, stopping the car in 5.1s with constant deceleration.
Calculate the acceleration of the car for the first 400m.
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Bonifacio

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Re: STUCK ON MOTION T_T
« Reply #1 on: February 11, 2011, 10:32:54 pm »
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WOW, what an idiot I am.
« Last Edit: February 11, 2011, 10:38:57 pm by Bonifacio »
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ttn

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Re: STUCK ON MOTION T_T
« Reply #2 on: February 11, 2011, 10:34:06 pm »
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Use the formula: d = ut + (at^2)/2

so:

400 = 0 + a(19^2) x 1/2
400 = 180.5a
a = 2.22m/s^2
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DannyN

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Re: STUCK ON MOTION T_T
« Reply #3 on: February 11, 2011, 10:42:14 pm »
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so the 5.1s doesnt affect the question in any way? BTW THANKS!
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schnappy

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Re: STUCK ON MOTION T_T
« Reply #4 on: February 11, 2011, 11:00:37 pm »
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No. Should be obvious since the braking happens AFTER 400m. You'll often be given excess information to try and trick you... last years paper had a questions, just had to apply dp = Impulse = Fd(t). They gave you a mass for the object...
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