circuit problem

[Shark 774]

This is a simplified heinemann question. Solution said that both of these circuits should have the same current flowing through them, but I thought the current in circuit A would be I = V/R, but in B it would be
I = 2V/R... help? (Note, voltage and resistors are identical in A & B)

[xZero]

the total current in circuit B would be twice the current in circuit A, however the currents through the resistor in both circuits are the same

eg. lets say that the first resistor in circuit B = r1 and the second be r2, the current going through r1 will be I=V/r1 and the current going through r2 will be I=V/r2 and the current going through the circuit A is I=V/r, but the resistance of r1, r2 and r are the same, hence I = V/r for all 3 resistors

[Shark 774]

the total current in circuit B would be twice the current in circuit A, however the currents through the resistor in both circuits are the same

eg. lets say that the first resistor in circuit B = r1 and the second be r2, the current going through r1 will be I=V/r1 and the current going through r2 will be I=V/r2 and the current going through the circuit A is I=V/r, but the resistance of r1, r2 and r are the same, hence I = V/r for all 3 resistors

Ahh right, how stupid! I was thinking of total current.

[schnappy]

Parallel EMF's no do give a higher EMF to the circuit, but if you're looking at current-limited supplies, you can get more out of them. (My understanding is batteries etc can only provide so much current at x V)