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June 15, 2025, 06:00:47 pm

Author Topic: Conditional Probability for Mean/Expected Values  (Read 1957 times)  Share 

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shinny

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Conditional Probability for Mean/Expected Values
« on: October 25, 2008, 08:06:44 pm »
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OK since my last thread utterly failed I'll just remake it. Basically, first thing, is conditional means on the course? And secondly, can someone explain how it works? I don't completely get it... What I came up with is:




And then E(X>k) is solved by integrating k to infinity (or whatever the upper bound of f( x) is) for ?
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pHysiX

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Re: Conditional Probability for Mean/Expected Values
« Reply #1 on: October 25, 2008, 08:17:29 pm »
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haha buddy, i think u can stop stressing coz it's not on the study design. from the probability i did as part of extra uni maths, i haven't even encountered these myself.
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shinny

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Re: Conditional Probability for Mean/Expected Values
« Reply #2 on: October 25, 2008, 09:11:04 pm »
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Bloody TSFX. This came up in the exam with the lambert-W function etcetc. Guess it really is ridiculous exam in every way possible <_<
MBBS (hons) - Monash University

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YR12 '08: Chemistry 47; Spesh 41; Methods 49; Business Management 50; English 43

ENTER: 99.70


dekoyl

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Re: Conditional Probability for Mean/Expected Values
« Reply #3 on: October 25, 2008, 11:27:48 pm »
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Bloody TSFX. This came up in the exam with the lambert-W function etcetc. Guess it really is ridiculous exam in every way possible <_<
Heh cool thanks for the heads up. The TSFX 2006 Exam 2 is on the bottom of my exam list. I heard its ridiculous but I'm interested in how hard it is.
Did you find it hard?

shinny

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Re: Conditional Probability for Mean/Expected Values
« Reply #4 on: October 25, 2008, 11:33:28 pm »
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Mmm..majority of it is acceptable but time-wise its quite difficult.
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ENTER: 99.70


dcc

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Re: Conditional Probability for Mean/Expected Values
« Reply #5 on: October 26, 2008, 09:13:38 pm »
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OK since my last thread utterly failed I'll just remake it. Basically, first thing, is conditional means on the course? And secondly, can someone explain how it works? I don't completely get it... What I came up with is:




And then E(X>k) is solved by integrating k to infinity (or whatever the upper bound of f( x) is) for ?


Lets say you had the randomly distributed variable X which follows a PDF function for which has the property .

If you know that , then first of all, find the area under the curve of from to .

It turns out that , so now define a new random variable Y which follows a PDF function with equation:

for . We multiply by the reciprocal of the above area to ensure that the area under the NEW curve is equal to 1.  We can see that .

So in this case, we have .

In general, this process can be summarised as:



It seems latex is down at the moment, hopefully that will be fixed soon.

shinny

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Re: Conditional Probability for Mean/Expected Values
« Reply #6 on: October 26, 2008, 09:35:14 pm »
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And do we need to know this? =T
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YR12 '08: Chemistry 47; Spesh 41; Methods 49; Business Management 50; English 43

ENTER: 99.70


dekoyl

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Re: Conditional Probability for Mean/Expected Values
« Reply #7 on: October 26, 2008, 09:51:01 pm »
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And do we need to know this? =T
I believe that this isn't in the course guide so we don't, thankfully.

dcc

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Re: Conditional Probability for Mean/Expected Values
« Reply #8 on: October 26, 2008, 09:51:48 pm »
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And do we need to know this? =T

Not at all :)

dekoyl

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Re: Conditional Probability for Mean/Expected Values
« Reply #9 on: October 26, 2008, 09:56:07 pm »
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Not at all :)
But somehow you know this. So props to you, wise sir.  ;D