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September 05, 2025, 06:16:53 pm

Author Topic: ATTENTION COBLIN  (Read 2201 times)  Share 

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Mao

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ATTENTION COBLIN
« on: November 13, 2008, 01:27:02 pm »
In a fuel cell, where the net flow of H+ is to the right, and the flow of electrons in the external circuit is also to the right [anode on the left, cathode on the right], which way does the anion electrolyte flow... if at all?

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Re: ATTENTION COBLIN
« Reply #1 on: November 13, 2008, 01:34:45 pm »
Oh crap, now that you mention this question, I think I actually skipped it altogether and forgot to go back and do it since you had to draw on the actual diagram o_O Uh oh.
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riadnicolas

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Re: ATTENTION COBLIN
« Reply #2 on: November 13, 2008, 01:38:21 pm »
yeh i pointed it towards the cathode assuming that the negatively charged h2po4 was going to the be attracted to the +
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Collin Li

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Re: ATTENTION COBLIN
« Reply #3 on: November 13, 2008, 01:40:09 pm »
Anions flow to the anode, to replace the loss of negative charge. (Like in a salt bridge)

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Re: ATTENTION COBLIN
« Reply #4 on: November 13, 2008, 01:40:42 pm »
I also assumed H2PO4- flow would oppose the electron flow, hence right-to-left on the diagram.
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Mao

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Re: ATTENTION COBLIN
« Reply #5 on: November 13, 2008, 01:41:21 pm »
thanks coblin
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Mao

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Re: ATTENTION COBLIN
« Reply #6 on: November 13, 2008, 01:45:58 pm »
WAIT

there is no electrostatic build-up of charges at the anode though... as the products (H+ from H2) are continuously migrating towards the cathode... doesn't that do the same thing as anions migrating towards the anode?

there is a limited amount of anode, if it does indeed move towards the anode, wouldn't the fuel cell eventually "go flat" when the electrolyte is depleted?

I have a feeling that they don't move at all.
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Re: ATTENTION COBLIN
« Reply #7 on: November 13, 2008, 01:57:47 pm »
Anions flow to the anode, to replace the loss of negative charge. (Like in a salt bridge)

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