Modulus how to sketch?

[TrueTears]

well i know the basics, eg f(x)=|x+2|, if x+2>0 x>-2 then f(x)=x+2. if x+2<0 x<-2 then f(x)=-x-2, then i'd just sketch those 2 separate graphs with those restrictions. However if i get something like |2sin(2x)| how would you sketch that?

[ell]

well i know the basics, eg f(x)=|x+2|, if x+2>0 x>-2 then f(x)=x+2. if x+2<0 x<-2 then f(x)=-x-2, then i'd just sketch those 2 separate graphs with those restrictions. However if i get something like |2sin(2x)| how would you sketch that?

sketch first, then reflect any part of the graph that is below the x-axis about the x-axis.

[dekoyl]

sketch first, then reflect any part of the graph that is below the x-axis about the x-axis.

Yep pretty much that. You will get "sharp points" or cusps(I think?)at the points where it reflects for .

Edit: As Coblin reminded me , it's not always a sharp point when reflecting. See below.

[Collin Li]

sketch first, then reflect any part of the graph that is below the x-axis about the x-axis.

Yep pretty much that. You will get "sharp points" or cusps(I think?)at the points where it reflects. That can't be differentiable.

Not necessarily. What about ?

[dekoyl]

Not necessarily. What about ?

Ah yes of course Thank you.

[TrueTears]

ah ty