Speed in Further

[lacoste]

An tennis ball under 'free fall' owing to gravity increases its speed (S) by 10m/s each second. Assuming that at the start the speed of the ball(object) was 0, the formula that relates S and time (t in seconds) is:

A. S=10t    B.S=10/t   C. S=t/10   D. S=5t  E. 20t

Could you also explain how you got the answer, many thanks!!

[Flaming_Arrow]

hint: v = u + at

[kurrymuncher]

V= u + at

V= 0 + 10(t)

V= 10t

[lacoste]

hint: v = u + at

Further doesn't use these Physics formulas.. just Speed=distance/time

[lacoste]

Thanks guys, is there another way without using v=u+at?

because i don't think that formula is in the further course?

[methodsboy]

WTH! there's motion in further

[Flaming_Arrow]

distance = speed * time

acceleration = speed / time

speed = acceleration * time

therefore S = at (given initial speed is 0)

[mypurpleundercracka]

what ch this in? were stuck on bloody statistics

[plato]

An tennis ball under 'free fall' owing to gravity increases its speed (S) by 10m/s each second. Assuming that at the start the speed of the ball(object) was 0, the formula that relates S and time (t in seconds) is:

A. S=10t    B.S=10/t   C. S=t/10   D. S=5t  E. 20t

Could you also explain how you got the answer, many thanks!!


The velocity, acceleration etc formulas for motion are not in the Further Maths Study Design.
Still, the question asked here is relevant to the Graphs and Relations module of Further.
Since speed is increasing at a constant rate of 10m/s each second, then a graph of S against time must produce a straight line (throught the origin) with a constant gradient of 10.
Hence S = 10t  (compare this with y = mx)

Just ignore the reference to "gravity".