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October 16, 2025, 08:21:44 pm

Author Topic: Recreational Problems (SM level)  (Read 92495 times)  Share 

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enwiabe

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Recreational Problems
« Reply #15 on: October 20, 2007, 03:26:40 pm »
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Let the record show that I was wrong! I misdivided something. :( I have brought shame to the spec community :P *commits suicide*

Ahmad

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« Reply #16 on: October 20, 2007, 03:38:20 pm »
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7. If f is continuous and f(x) + f(-x) = x^2. What is int (-1 to 1) f(x) dx?

8. Let f(x) = (3x^4 + 16)/(2x^4 + 11). Find the whole number nearest to f(2^32).

9. Find the smallest possible constant A such that ln x <= Ax^2 for all x > 0.
« Last Edit: December 14, 2007, 07:50:06 pm by coblin »
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cara.mel

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« Reply #17 on: October 20, 2007, 04:32:02 pm »
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for #4, why does tan(x)*tan(90-x) = 1?

That and #1 are the only ones I can work out how to do so far :( (without simply asking the calculator)

enwiabe

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« Reply #18 on: October 20, 2007, 04:53:47 pm »
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9. A = e^(1/2)

Ahmad

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« Reply #19 on: October 20, 2007, 04:54:04 pm »
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tan(x) * tan[90 - x] = sin(x) / cos(x) * sin[90 - x] / cos[90 - x]

Using complementary angles:

= sin(x) / cos(x) * cos(x) / sin(x) = 1

What sort of problems do you guys want? And what sort of difficulty? If I get feedback I can attract a wider spectrum of people.
« Last Edit: December 14, 2007, 07:50:25 pm by coblin »
Mandark: Please, oh please, set me up on a date with that golden-haired angel who graces our undeserving school with her infinite beauty!

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enwiabe

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« Reply #20 on: October 20, 2007, 04:55:42 pm »
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8. Should be 1.

Ahmad

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« Reply #21 on: October 20, 2007, 04:59:46 pm »
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Try to post solutions, that way we can discuss methods, spot mistakes etc. I got something different for that one.
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Toothpaste

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« Reply #22 on: October 20, 2007, 11:48:10 pm »
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7. If f is continuous and f(x) + f[-x] = x^2. What is int (-1 to 1) f(x) dx?

f(x) = x^2 / 2  , making f(x) + f[-x] = x^2 true.

int (-1 to 1) f(x) dx

=   [x^3 / 6](-1 to 1)
= 1/6 -  -1/6
= 2/6
= 1/3

I got this by just looking at it, so um, I'm probably wrong. :(
« Last Edit: December 14, 2007, 07:50:43 pm by coblin »

AppleXY

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« Reply #23 on: October 20, 2007, 11:52:19 pm »
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Used symmetry and int. properties for 7. Stil trying. :p

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Ahmad

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« Reply #24 on: October 21, 2007, 07:09:31 am »
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Quote from: Toothpick
7. If f is continuous and f(x) + f[-x] = x^2. What is int (-1 to 1) f(x) dx?

f(x) = x^2 / 2  , making f(x) + f[-x] = x^2 true.

int (-1 to 1) f(x) dx

=   [x^3 / 6](-1 to 1)
= 1/6 -  -1/6
= 2/6
= 1/3

I got this by just looking at it, so um, I'm probably wrong. :(

You proved it for one such f(x), which yields the correct answer. This is a correct method, but can you prove it for f(x) in general?  :)
« Last Edit: December 14, 2007, 07:51:14 pm by coblin »
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Ahmad

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« Reply #25 on: October 21, 2007, 07:42:55 am »
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10.  Evaluate int (-pi/2 to pi/2) sin(x) sin[2x] dx.

11. Evaluate int (-pi/4 to pi/4) sin^2(x) / cos^2(x) dx.

12. Let f(x) = sin^4(x) + cos^4(x). Find the 100th derivative of f. [hide=hint](sin^2(x) + cos^2(x))^2 = 1 [/hide]
« Last Edit: December 14, 2007, 07:51:28 pm by coblin »
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Khangfu

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Recreational Problems
« Reply #26 on: October 21, 2007, 11:04:50 am »
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7. 2/3 - (-1,1)f(-x)dx ?

Ahmad

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« Reply #27 on: October 21, 2007, 11:07:35 am »
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You should be able to evaluate it exactly. Here's a hint, split it up into (-1 to 0) and (0 to 1). On (-1 to 0) make the substitution u = -x.

=)
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asa.hoshi

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« Reply #28 on: October 22, 2007, 06:51:19 am »
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10. 4/3
11. -pi/2 + 2
I KNOW WHAT YOU DID LAST SUMMER!!

asa.hoshi

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« Reply #29 on: October 22, 2007, 06:57:24 am »
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5. x=1, x= [-3+squareroot(5)]/2, x= [-3-squareroot(5)]/2
I KNOW WHAT YOU DID LAST SUMMER!!