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May 23, 2024, 02:37:42 pm

Author Topic: 2011 UMAT Question Thread  (Read 13159 times)  Share 

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shinny

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Re: 2011 UMAT Question Thread
« Reply #60 on: April 18, 2011, 10:27:01 pm »
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I'm thinking similarly to Zien by going across the rows, but if you use maths you get:
1.
2.
3.



Which from there, I'm sure you can solve it to mean it equals C.
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Zien

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Re: 2011 UMAT Question Thread
« Reply #61 on: April 19, 2011, 10:11:50 am »
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^That's a very interesting method! Thanks for sharing that with us. :)

Does Andiio have the suggested answer for the question?
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Re: 2011 UMAT Question Thread
« Reply #62 on: April 19, 2011, 04:33:36 pm »
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yea that's what i tried, just couldn't confirm whether it would equal black + white, all you can confirm is that there would be 2 colours, correct?
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Re: 2011 UMAT Question Thread
« Reply #63 on: April 22, 2011, 12:56:54 pm »
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Hmm that methods very interesting. However I used Zien's method to get B

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Re: 2011 UMAT Question Thread
« Reply #64 on: April 26, 2011, 08:37:45 pm »
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can someone help explain what's happening in this question?  I'm so confused :S



I get that one of them is 'second cousin six generations removed', but what about the great-great-great-great grandfather answer? How do we know he has two GGsons and two 7GGsons?  Also, why would it be D instead of C?

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Re: 2011 UMAT Question Thread
« Reply #65 on: May 01, 2011, 10:16:40 am »
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Would be great if someone could explain this question. I also do not know how the 2nd relationship with found nor why C is wrong.

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Re: 2011 UMAT Question Thread
« Reply #66 on: June 05, 2011, 09:51:04 pm »
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More than a month, so bump for previous question. Don't think people are aware of it

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Re: 2011 UMAT Question Thread
« Reply #67 on: June 15, 2011, 09:06:15 pm »
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Its indeed a hard one, I got stuck at the same point as you

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Re: 2011 UMAT Question Thread
« Reply #68 on: June 17, 2011, 11:46:36 am »
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Can someone look at these 2 questions and explain why in 18) they found the % of survival for 1 class as %survive after 5 years/%survive after 1 year? as the chance of surviving 5 years after 1 year In 20) however they found only the %survive after 5 years and multiplied them together. Shouldn't they divide by % survive after 1 year for both categories then multiply?


KL_tutor

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Re: 2011 UMAT Question Thread
« Reply #69 on: June 18, 2011, 08:12:09 pm »
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Can someone look at these 2 questions and explain why in 18) they found the % of survival for 1 class as %survive after 5 years/%survive after 1 year? as the chance of surviving 5 years after 1 year In 20) however they found only the %survive after 5 years and multiplied them together. Shouldn't they divide by % survive after 1 year for both categories then multiply?


You've basically got to look really closely at the content of the question. If I was doing it I would have taken the question and underlined the following:
"If you have had colon cancer and have survived for a year, according to the data, what is the chance that you will survive for 5 years?"

Next thing I would've done is make it simpler by forgetting percentages and looking at it as numbers of people. So say there were 1000 people with colon cancer. 800 survive for one year and 200 do not. 600 survive for 5 years and 400 do not. Those 400 include the 200 that did not survive for one year. Thus out of the 800 that survived for one year, 600 survived for five years and 200 did not. Thus you can say it's a 75% survival chance if you are amonsgt those 800.

"If you have been diagnosed with lung and breast cancers, according to the statistics, what are the chances that you will survive for 5 years after treatment?"

Key thing is that time = 0. The person has just been diagnosed. If 1000 people were diagnosed with lung cancer, only 100 of them would survive for 5 years. If 1000 people were diagnosed with breast cancer, 820 of them would survive for 5 years. If one was diagnosed with both, then (although not sure if this is a proper scientific conclusion but I guess you just have to go with it), one could say they had a 10% chance of surviving the lung cancer, and if they were amongst the 100 that managed to survive the lung cancer, there was an 82% chance that they would furthermore survive the breast cancer. That means if there were 1000 people diagnosed with both, around 82 would manage to survive both in 5 years. So that's how they came to the answer of 8.2%

Does that help?
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Re: 2011 UMAT Question Thread
« Reply #70 on: June 18, 2011, 10:16:12 pm »
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So much clearer now thanks a lot KL :)

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Re: 2011 UMAT Question Thread
« Reply #71 on: June 19, 2011, 11:41:29 am »
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Hey guys,

I need a further explanation to this question as its confusing me. It says that the team that lost the greatest number of games scores the highest total. This implies that that team can either lose 2 or 3 games right?

Also the first part of the solutions state that they cannot score 4, 5, 6 but that doesn't make sense. If they scored 4 and the other team scored 3 in the next game they score 5 and the next team score 6 won't they still lose 2 games?

This statement completely lost me "The highest total of two scores achieved by this team is greater than the total of at least 7 (6 and at least 1) achieved by some other team. So this team scored 5 and 3 for a total of 8. "

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Re: 2011 UMAT Question Thread
« Reply #72 on: July 19, 2011, 08:41:12 am »
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Come on guys please help!