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October 21, 2025, 08:17:31 pm

Author Topic: Puffy (Paulsterio + Luffy) 2011 - Specialist Maths - ATARNotes Trial Examination  (Read 33259 times)  Share 

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costa94

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October 14, 2011, 11:11:13 pm - Hidden.

nacho

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0.5 for this
i rate you a 0.5 as a person
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costa94

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October 14, 2011, 11:28:18 pm - Hidden.

paulsterio

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Really? I'd say heffernan would be a 3-4.

I wouldn't rate heffernan below VCAA, I think they're pretty similar in level, but it would depend though
I'm guessing we would put something like Insight as a 1 or a 2?

EDIT: I'm stating to drift off-topic again, sorry guys I'll keep quiet now.

Off topic I know, but last comment, YES I AGREE WITH YOU! Insight would be as easy as you can get! :P

0.5 for this
I personally don't think that your comments are appropriate, although I understand that you may be joking, your comments are "spam-like" and generally not constructive



taiga

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no one can stop you for giving a paper a shit rating, but i'd like to see you justify your rating in order to make the post actually constructive.

if you're trying to be funny, cool man
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thushan

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Had a quick scan of the paper, it's well written, and I think I would actually rate this a 4-6; I say this because VCAA papers are actually relatively difficult - well at least the 2008 paper was. But if you can match VCAA you're doing well.

On a side note, Kilbaha is awesome, my fav Spesh exam company!
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99.96

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I'll give this a shot, btw this year's exam has 11 questions ;)
2010: Physics | Methods
2011: Specialist Maths [47]| Business Management [47]| Further Maths [50]| English [39]
ATAR: 99.30

Tutoring Specialist and Further Maths

jane1234

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Good job guys!
I just did the paper and yeah, have to agree with thushan in that it's fairly straightforward. Probably on par with VCAA, or at least the ones I've done, in that there are no overly complicated questions. Nonetheless, a great practice exam! :)

99.96

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^^^ how exactly do you do 8a and b.
I did them but i think its wrong.
2010: Physics | Methods
2011: Specialist Maths [47]| Business Management [47]| Further Maths [50]| English [39]
ATAR: 99.30

Tutoring Specialist and Further Maths

paulsterio

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Had a quick scan of the paper, it's well written, and I think I would actually rate this a 4-6; I say this because VCAA papers are actually relatively difficult - well at least the 2008 paper was. But if you can match VCAA you're doing well.

On a side note, Kilbaha is awesome, my fav Spesh exam company!

hmm yeah that's true, vcaa papers for specialist maths exam 1 are actually far more difficult than vcaa exam 1's for methods, i was actually quite surprised with the jump from methods to spesh! D:

I'll give this a shot, btw this year's exam has 11 questions ;)
yeah i know, but I ran out of marks on my exam, I'd already allocated 40 marks by question 10 and it was too hard to try to cut down on marks :P

Good job guys!
I just did the paper and yeah, have to agree with thushan in that it's fairly straightforward. Probably on par with VCAA, or at least the ones I've done, in that there are no overly complicated questions. Nonetheless, a great practice exam! :)
thanks jane! :D it's nice when people actually do it hahah :) i guess i get a feeling of satisfaction :P LOL!

jane1234

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^^^ how exactly do you do 8a and b.
I did them but i think its wrong.

You turn z + 1/z = k into a quadratic, then use the quadratic formula to solve for z.
Using the discriminant, we know that if k^2 - 4 >= 0 then z will lie on the real axis.
If not, then sqrt(k^2-4) will be an imaginary number.
Let z = x + yi, and x = k/2, y = sqrt(4-k^2)/2 (you have to times k^2-4 by -1 because you are after the imaginary PART of z).
Square both x and y, add them together and you get x^2 + y^2 = 1, showing that z either lies on the real axis or on the unit circle.
Part b is easy once you have done this. :)

paulsterio

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You turn z + 1/z = k into a quadratic, then use the quadratic formula to solve for z.
Using the discriminant, we know that if k^2 - 4 >= 0 then z will lie on the real axis.
If not, then sqrt(k^2-4) will be an imaginary number.
Let z = x + yi, and x = k/2, y = sqrt(4-k^2)/2 (you have to times k^2-4 by -1 because you are after the imaginary PART of z).
Square both x and y, add them together and you get x^2 + y^2 = 1, showing that z either lies on the real axis or on the unit circle.
Part b is easy once you have done this. :)

Thanks Jane, you beat me to it! :P

zool3

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solutions for this?

paulsterio

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zool3

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ohh thank you! :D btw, have you updated the 2011 insight exam 1?