ASX4Life's Methods Questions

[Asx4Life]

VCAA 2009 Exam 2. Can someone please explain Question 3G? Thanks

[aznxD]

Trial and error.
Work out S1 (n=1), S2 (n=2), S3 (n=3) and so on until the top value of your answer is less than 0.45

[Greatness]

I think you can solve it on the caluclator like type out the matricies to the power of n and solve it for n

[Asx4Life]

Hey guys, I need help with Heffernan 2010 Exam 2.
Question 3f.
In this question are we supposed to calculate the end distance from the end of the pole from reference of when y=0 or from the ground level which is abit higher. They calculated it from above the ground which was 9.0374m, but I thought the question said "find the horizontal distance of the end of the pole".

Maybe someone who has already done this paper could help me? Oh ya, this exam is very interesting haha.

[Phy124]

Hey guys, I need help with Heffernan 2010 Exam 2.
Question 3f.
In this question are we supposed to calculate the end distance from the end of the pole from reference of when y=0 or from the ground level which is abit higher. They calculated it from above the ground which was 9.0374m, but I thought the question said "find the horizontal distance of the end of the pole".

Maybe someone who has already done this paper could help me? Oh ya, this exam is very interesting haha.

"Find the horizontal distance of the end of the pole from the fence. Express your answer correct to 3 decimal places."

So they are asking the distance between x = 0 and the x-intercept of the equation of the pole

It says the gradient of the pole is 6.5, so you can calculate the the x value which the pole and the "pile" intersect by making h'(x)=-1/6.5.

Then put the acquired x-value back into h(x) which will give you the y-value for which they intersect.

After this you do y - y1 = m (x - x1). Then make y = 0 for this equation and obtain the x intercept.

The distance between x = 0 and this x intercept should be the answer.

I can write a solution and scan it if you would like.

[Asx4Life]

Yeah, I got that, but do we have to calculate the end of the pole meaning the normal line goes right to the x-intercept(y=0)? cause the question says the pole is placed all the way down to the bottom of the rubbish

[Greatness]

Yeah, I got that, but do we have to calculate the end of the pole meaning the normal line goes right to the x-intercept(y=0)? cause the question says the pole is placed all the way down to the bottom of the rubbish

This is a good question Would be good if there's something smilar this year!
But yeah you want to find when the pole is touching the ground, so find the x intercept.