So there's been a few questions regarding the proper notation to be used on the exam, so I thought it's probably time to make a thread
I'm assuming this is right, but feel free to pick me up on anything I've missed:
Normal DistributionThe range of scores on a particular test are such that they hold a mean of 60 with a standard deviation of 4.NORMAL CDFa) Find the probability of a student's scores lie between 55 and 62On the TI-Nspire;
})
On the classpad;
})
On paper:
Let X be the range of scores of students on the test.
)
 = 0.5858)
NORMAL PDFb) Find the probability that a student's score is 61On the calculator;
})
On paper:
Let X be the range of scores of students on the test.
 = 0.0967)
INVERSE NORMALc) 75% of students passed the test. Find the score needed to pass the test.On the calculator;
)
On paper:
Let X be the range of scores of students on the test.
Let a be the minimum value needed to pass, Find a such that
 = 0.75)
 = 0.25)
Therefore a score of 57.3020 is needed to pass.
Binomial DistributionBinomPDFd) The probability that a particular student passes the test is 0.4.i) If this student sits 3 tests that are independent to the other, what is the probability that the student passes 2 out of 3 tests.On the calculator;
)
On paper:
Let Y be the performance of the student in the 3 tests
)
 = 0.288)
BinomCDFii) This particular student needs to pass at least one of the tests to make his parents happy. What is the probability that his parents will be happy?On the calculator;
)
On paper:
Let Y be the performance of the student in the 3 tests
 = 0.784)
Number of Trialsiii) The student is now getting very worried about his parents. To ensure that the probability that his parents are happy is 0.95, how many tests will he have to sit if he has to pass at least one of them?On paper:
Let Y be the performance of the student in the m number of tests
Find m such that
 > 0.95)
 > 0.95)
 < 0.05)
^0(0.6)^{m} < 0.05)
^{m} < 0.05)
the student will need to sit 6 tests.
Hopefully that's all correct!
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