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January 15, 2026, 02:57:38 pm
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Author Topic: Principle Argument:  (Read 8187 times)  Share 

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tony3272

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Principle Argument:
« on: November 10, 2011, 10:43:39 am »
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Was it or ?
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golden

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Re: Principle Argument:
« Reply #1 on: November 10, 2011, 10:45:26 am »
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11pi/12.

Would I lose all marks if I didn't do it that way but instead did:
Multiply top and bottom by the conjugate of the bottom, then do all the calculations etc. etc. and end up with invtan(answer)...
Would I get 1 mark at least?
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chrysalis

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Re: Principle Argument:
« Reply #2 on: November 10, 2011, 10:46:29 am »
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I made a careless mistake and got -5pi/12.. NUUU! >_<

And yeah, 11pi/12.
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HarveyD

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Re: Principle Argument:
« Reply #3 on: November 10, 2011, 10:46:49 am »
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I put 11pi/12 + 2*pi*k
would I lose a mark? :S
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kenny_

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Re: Principle Argument:
« Reply #4 on: November 10, 2011, 10:50:24 am »
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Quote from: HarveyD on November 10, 2011, 10:46:49 am
I put 11pi/12 + 2*pi*k
would I lose a mark? :S

You probably will cause Principle Arg -pi < x =< pi
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Zebra

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Re: Principle Argument:
« Reply #5 on: November 10, 2011, 10:52:10 am »
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yeah it was 11pi/12
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dopplereffect

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Re: Principle Argument:
« Reply #6 on: November 10, 2011, 10:58:52 am »
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If Arg didn't have a restriction then there would be infinite values of k.
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Asx4Life

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Re: Principle Argument:
« Reply #7 on: November 10, 2011, 10:59:59 am »
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I'm gonna learn from Zebra to not look at the answers :D
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b^3

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Re: Principle Argument:
« Reply #8 on: November 10, 2011, 11:12:07 am »
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Arrrr shot I did -pi/12. Dam finally realised how to do the question with 6 mins on the clock, must have made a stupid error :(
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tiktokcheekaboom

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Re: Principle Argument:
« Reply #9 on: November 10, 2011, 11:14:10 am »
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Me too, I also got -pi/12 D:
Are there solutions up for this? I still can't think where I went wrong...
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b^3

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Re: Principle Argument:
« Reply #10 on: November 10, 2011, 11:16:06 am »
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Worked it out. When we did the angle for each part of the top and bottom oin polar form, for the top I took the angle as 2pi/3 when we should have used -pi/3 cause for the arg things tan is restricted to -pi/2 to pi/2.
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HarveyD

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Re: Principle Argument:
« Reply #11 on: November 10, 2011, 11:18:35 am »
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hmm someone give me an opinion on what marks i would get for this please D: so paranoid

i worked out
that the angle is -13pi/12
then below it wrote 11pi/12 (but didn't specify why)

then drew an arrow up to show that theta would be 11pi/12 + 2*pi*k for k element of real
since z = rcis theta

so I'd lose a mark for that last step yeah?
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kenny_

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Re: Principle Argument:
« Reply #12 on: November 10, 2011, 11:18:49 am »
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Quote from: b^3 on November 10, 2011, 11:16:06 am
Worked it out. When we did the angle for each part of the top and bottom oin polar form, for the top I took the angle as 2pi/3 when we should have used -pi/3 cause for the arg things tan is restricted to -pi/2 to pi/2.

arg is restricted from -pi to pi, 2pi/3 would still work, it's because the angle was in the 4th quadrant. positive x, negative y
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tiktokcheekaboom

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Re: Principle Argument:
« Reply #13 on: November 10, 2011, 11:19:38 am »
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Isn't the argument on the bottom supposed to be -pi/4 according to the restrictions on inverse tan? If it is actually 3pi/4, then I know where I went wrong T_T

DARN! D:
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chrysalis

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Re: Principle Argument:
« Reply #14 on: November 10, 2011, 11:20:59 am »
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It was 3pi/4 because it was in the second quadrant.
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