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November 02, 2025, 02:53:56 pm

Author Topic: VCE Methods Question Thread!  (Read 5771817 times)  Share 

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soNasty

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Re: VCE Methods Question Thread!
« Reply #4755 on: May 12, 2014, 07:29:34 pm »
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@Zealous i think you could do it either way though.. since [-2,inf) or [2,inf) would still give us a 1:1 function

Zealous

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Re: VCE Methods Question Thread!
« Reply #4756 on: May 12, 2014, 07:32:29 pm »
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@Zealous i think you could do it either way though.. since [-2,inf) or [2,inf) would still give us a 1:1 function
Yep, they will both give a 1:1 functions. I was just thinking about the fact that they specified "largest set".
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Rishi97

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Re: VCE Methods Question Thread!
« Reply #4757 on: May 12, 2014, 08:48:37 pm »
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I have my methods sac next week on power functions, inverses and circular functions. How likely is it that I will have a addition of ordinates question?
I seriously hate adding/subtracting/multipling ordinates :(
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Reus

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Re: VCE Methods Question Thread!
« Reply #4758 on: May 12, 2014, 10:19:35 pm »
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I have my methods sac next week on power functions, inverses and circular functions. How likely is it that I will have a addition of ordinates question?
I seriously hate adding/subtracting/multipling ordinates :(
I have mine tomorrow haha! And same, ordinates is my only weakness, my teacher emphasised on subtraction of ordinates being on the SAC, and since CAS is allowed ill be fine, and so should you! Good luck :)
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soNasty

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Re: VCE Methods Question Thread!
« Reply #4759 on: May 13, 2014, 02:38:28 pm »
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Solve 2sin^2(pix)+ 3cos(pix)-3=0 over [0,2pi]
I'm not getting enough answers. Would the new domain when solving be 2pi^2? This is weird lol

Thorium

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Re: VCE Methods Question Thread!
« Reply #4760 on: May 13, 2014, 03:32:01 pm »
+1
Solve 2sin^2(pix)+ 3cos(pix)-3=0 over [0,2pi]
I'm not getting enough answers. Would the new domain when solving be 2pi^2? This is weird lol

Here is wat i did and I got eight ten solutions.

EDIT: for the last step, i forgot to also include 4 and 6 as well
« Last Edit: May 13, 2014, 03:38:08 pm by Thorium »
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soNasty

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Re: VCE Methods Question Thread!
« Reply #4761 on: May 13, 2014, 04:30:38 pm »
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how are you getting 11/3 and 17/3 if the domain is only over 0 to 2 pi?

achre

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Re: VCE Methods Question Thread!
« Reply #4762 on: May 13, 2014, 05:00:32 pm »
+1
2pi is about equal to 6.2, and 17/3 is going to be some number smaller than 6 (because 18/3 = 6). It's actually a useful skill, especially when sketching circular functions, to figure out what the value of a number roughly is. (sqrt(3) is going to be 1.something, pi/3 will be a little bit larger than 1, etc., etc.)

juzza12

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Re: VCE Methods Question Thread!
« Reply #4763 on: May 13, 2014, 09:48:20 pm »
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Super quick question guys; On exam papers do examiners mind us writing ln(x) apposed to loge(x)?

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Re: VCE Methods Question Thread!
« Reply #4764 on: May 13, 2014, 09:59:44 pm »
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Super quick question guys; On exam papers do examiners mind us writing ln(x) apposed to loge(x)?

I don't think they mind, given that ln(x) and loge(x) is practically the same thing

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Re: VCE Methods Question Thread!
« Reply #4765 on: May 13, 2014, 10:13:26 pm »
+2
They CAN'T mind. Calculators say ln x, lots of maths textbooks and authors use ln x...it would be like saying chemistry doesn't recognise calling nitrogen monoxide nitrogen (II) oxide.
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Re: VCE Methods Question Thread!
« Reply #4766 on: May 15, 2014, 12:15:12 pm »
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Could someone please show me the steps to work out the following. I am having a serious mental blank here, because it seems that I am missing a vital step
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Phy124

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Re: VCE Methods Question Thread!
« Reply #4767 on: May 15, 2014, 12:48:39 pm »
+5


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Re: VCE Methods Question Thread!
« Reply #4768 on: May 15, 2014, 05:42:54 pm »
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Hey guys, i'm having trouble writing a hybrid function;

how would i go about rewriting y=-0.05*|x²-10x+21|+6 , 0≦x≦7 as a hybrid function

Thanks in advance :D

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Re: VCE Methods Question Thread!
« Reply #4769 on: May 15, 2014, 05:57:03 pm »
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Thank you very much.I cannot believe I had a mental blank with such an easy question.
Now could you guys please help me with the following question(s):
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