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January 10, 2026, 01:36:29 am

Author Topic: VCE Methods Question Thread!  (Read 5877151 times)  Share 

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LiquidPaperz

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Re: VCE Methods Question Thread!
« Reply #6405 on: October 30, 2014, 12:01:47 am »
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what are the conditions for exam 1 and 2?

exam 1 pencil 2B or HB?
exam 2 pen or is pencil allowed?

im unaware of what were meant to complete it in for each exam

thanks

keltingmeith

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Re: VCE Methods Question Thread!
« Reply #6406 on: October 30, 2014, 12:13:28 am »
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From 'Stupid' Exam Questions:

Quote
Do I have to write in pen? I much prefer pencil...
That's okay. Often teachers will urge you to write in pen so that there's no chance of the graphite on the paper becoming too smudged to read. If you do use pencil, make sure it's well sharpened and you're writing dark (not lightly), and you shouldn't run into this problem! No matter what, it is highly suggested you do graphs in pencil, though.

On what to bring to each exam, for methods you should be bringing a pen and pencil to both exams (or just pencils if you don't want to use pen). To memory, you'll need a HB for exam 2's multiple choice section.

chocolatechipcookies

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Re: VCE Methods Question Thread!
« Reply #6407 on: October 30, 2014, 11:02:52 am »
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Has anyone done the 2014 Kilbaha trial exam?

I do not understand any of the solutions for the extended response part of Exam 2 :'(

Blondie21

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Re: VCE Methods Question Thread!
« Reply #6408 on: October 30, 2014, 02:54:07 pm »
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What would be the domain of the inverse of
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Yacoubb

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Re: VCE Methods Question Thread!
« Reply #6409 on: October 30, 2014, 03:00:26 pm »
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What would be the domain of the inverse of

Domain of the inverse is the range of the function. Therefore, dom of inverse = R.

Blondie21

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Re: VCE Methods Question Thread!
« Reply #6410 on: October 30, 2014, 03:16:37 pm »
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Domain of the inverse is the range of the function. Therefore, dom of inverse = R.

The range of f(x) isn't R though?
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Blondie21

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Re: VCE Methods Question Thread!
« Reply #6411 on: October 30, 2014, 03:32:22 pm »
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BTW why is my answer to this general solutions q wrong?

Q: Find the general solution of



3x = and 3x =

x = and x =

The ans says x =

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LiquidPaperz

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Re: VCE Methods Question Thread!
« Reply #6412 on: October 30, 2014, 05:28:51 pm »
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i know this is a bit of a weird question.

but on the exam if your presented with a problem you dont know, worded/arithmetic problem you cant get your head around, how do you solve it?

- whats the process you go through? do you evaluate alternatives etc

Brunette15

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Re: VCE Methods Question Thread!
« Reply #6413 on: October 30, 2014, 06:04:29 pm »
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Can someone please help me with this question? The answer is 6 but I don't know how to get to it...
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Robert123

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Re: VCE Methods Question Thread!
« Reply #6414 on: October 30, 2014, 06:39:25 pm »
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i know this is a bit of a weird question.

but on the exam if your presented with a problem you dont know, worded/arithmetic problem you cant get your head around, how do you solve it?

- whats the process you go through? do you evaluate alternatives etc


Generally drawing a diagram can help. If not, flipping through my rule book to see if anything magical pop up. If this still doesn't work, then I generally resort into an emotional breakdown haha.

Can someone please help me with this question? The answer is 6 but I don't know how to get to it...

Since this is a probability density function problem, the area under the curve should equal 1. So firstly, integrate the modulus section (note, due to the restricted domain, you only can remove the
Modulus sign because it is all going to be multiple by -1, this then become 1-x).
This should give you the value of 0.5. This mean the area for the 0.1 section is 1-0.5=0.5 since this is going to be a rectangle with a height of 0.1, the length will be 5. Add this to your first terminal (1) and you should get the answer 6.

AngelWings

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Re: VCE Methods Question Thread!
« Reply #6415 on: October 30, 2014, 10:49:28 pm »
+1
Quick question in writing on the exam, so I was working through VCAA 2009, Exam 1 - Question 1b. and when I was working through the question I had a problem... so the amount of lines that were given on the exam wasn't enough for me to fully write my answer in (I had to go all the way to the bottom of the page) but if I were to go over the lines, would that still be okay? I'm just paranoid in terms of what they'll take as my answer in the end since I'm going over the lines (just happens to be that one question so far)...

Not sure if you do it already, Indefatigable Lover, but draw a line in the middle if you look at the question and think "I'm definitely going to go over." Personally, squiggly line's better and takes less than a second. Extra space. Check. Just note that you should probably highlight/box/do whatever you're used to at the end to make sure they see your final answer.
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IndefatigableLover

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Re: VCE Methods Question Thread!
« Reply #6416 on: October 30, 2014, 10:54:52 pm »
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Not sure if you do it already, Indefatigable Lover, but draw a line in the middle if you look at the question and think "I'm definitely going to go over." Personally, squiggly line's better and takes less than a second. Extra space. Check. Just note that you should probably highlight/box/do whatever you're used to at the end to make sure they see your final answer.
Haha thanks for the tip AngelWings and yeah you're right, I already do that with my responses (using arrows to indicate where they should be following my answers before marking my final answer with a double slant LOL)

huynhiiee

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Re: VCE Methods Question Thread!
« Reply #6417 on: October 30, 2014, 11:01:14 pm »
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First post yay. I am probably burnt out.
Vcaa 2011
The normal to the curve with equation y= x^3/2+x at the point (4,12) is parallel to the straight line with equation:
I got y=13-x/4 which is 4y+x=52
Answer is 4y+x=7

wow dw just got it. same gradient
« Last Edit: October 30, 2014, 11:09:37 pm by huynhiiee »

IndefatigableLover

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Re: VCE Methods Question Thread!
« Reply #6418 on: October 30, 2014, 11:01:59 pm »
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Hey,

Could someone please help me with 2007 VCAA exam 2, Q2(G)? I would upload a screen shot but I'm not too sure which information from Q2 is relevant.

I spent a few minutes re-reading the stem of the question but I can't seem to find what time would deem Tazzy Jones' recovery of the diamond successful.

So far, I have calculated the total time he takes to recover the diamond (1279/16 minutes) but I don't know why we have to deduct this figure from 80 minutes. Why is 80 minutes the time to beat?

Any help would be appreciated!
Haha just did this paper today and luckily I got this question right!

So essentially from your answer from Question 2e. you would have gotten 8/3 using -> however realistically Tasmania Jones has one shot to get the diamond since he can't drop it halfway and pick it up afterwards and all... so basically your answer from Question 2e is halved to 4/3 (just chose one of the fractions I guess) which is equal to 80 minutes when you convert from hours to minutes giving you the overall total time :) From there you would just do this:





Therefore he has 1/16 minutes left to spare or 3.75 seconds when you convert from minutes to seconds :)

Valyria

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Re: VCE Methods Question Thread!
« Reply #6419 on: October 31, 2014, 08:53:59 am »
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So essentially from your answer from Question 2e. you would have gotten 8/3 using -> however realistically Tasmania Jones has one shot to get the diamond since he can't drop it halfway and pick it up afterwards and all... so basically your answer from Question 2e is halved to 4/3 (just chose one of the fractions I guess) which is equal to 80 minutes when you convert from hours to minutes giving you the overall total time :) From there you would just do this:

I see where you are coming from but I'm still not sure to why we halve 8/3. I understand he has to make a smooth trip without any interruptions but why would this cause 8/3 to be divided by 2?

Thanks!
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