I use this method too although tbh I don't understand it.. I just know how to do it. How would you show the working out using this method though? I mean I don't think 0.5/(0.5+0.7) is enough for 2-3 marks.
This would never be a 3 mark question and for 2 marks its sufficient. If its a 3 mark question they would have to be asking for both steady state probabilities, in which you just to Pr(B) = 1 - Pr(A) when you figured out Pr(A) or otherwise using the steady state formula twice.
A B
A [ p 1-n ]
B [ 1-p n ]
Theres several ways to think about it, but its methods and methods doesn't require you to understand the deep intrinsic parts of the mathematics, rather just know how to use them. Think of it this way, theres a certain chance A changes to B, and 1 - (that chance) is the chance B changes to A. As your approach an infinite amount of changes, the probability of being A or B will be the probability of sticking with A or B during a change, divided by the sum of the two probabilities involving a change. The trend will be
The long term Pr(A) = 1-n / (1-n + 1 - p)
The long term Pr(B) = 1-p / (1-n + 1 - p)