VCE Methods Question Thread!

[Orb]

Assuming a relatively similar difficult as last year what ss could I expect with:
Sac's: 90/100
GA1: 35/40 or 34/40
GA2: 63/80   Thanks ^.^

Wrong thread but somewhere in the vicinity of 38-40

[theshunpo]

ARRRGGHH! GUYS FOR A GENERAL SOLUTION QUESTION.

I WROTE THE BASE ANGLE AS PI/3 INSTEAD OF PI/6

SO MY ANSWERS WERE BOTH WRONG because of the incorrect base angle!!!! DO I GET METHOD MARKS? OR ARE GENERAL SOLUTION QUESTIONS ONLY REWARD ANSWER MARKS?

Arghh my method was right but my answer was wrong

Was there a general solutions question? I'm pretty sure it had a restricted domain.

[anna.xo]

Was there a general solutions question? I'm pretty sure it had a restricted domain.

True..[0, pi]

[Blondie21]

Can someone please explain how to do q3 di of 2013 exam 2? I don't understand what VCAA did

[M_BONG]

Was there a general solutions question? I'm pretty sure it had a restricted domain.

yup, what i meant to say is i used the general solution method to find specific solutions within domain (subbing values into general sln). I got the base angle wrong though!!! will i still get method marks?

i wrote pi/6 instwad of pi/12

[faredcarsking123]

2007 Exam 2 5fii) How do we know to use from 20 to 30?

2011 Exam 2 4f) Why do we want dT/dx to be less than or equal to zero?

Thanks

[Blondie21]

why is this wrong? 2013 exam 2 q

[bovawatkins]

could someone please explain to me why the answer is 'b' and not 'e'?? Cheers

Question 22
The graph of a differentiable function f has a local maximum at (a, b), where a < 0 and b > 0, and a local
minimum at (c, d), where c > 0 and d < 0.
The graph of y = –|f(x – 2)| has
A. a local minimum at (a – 2, –b) and a local maximum at (c – 2, d)
B. local minima at (a + 2, –b) and (c + 2, d)
C. local maxima at (a + 2, b) and (c + 2, –d )
D. a local minimum at (a – 2, –b) and a local maximum at (a – 2, – d)
E. local minima at (c + 2, –d) and (a + 2, –b)

[Jason12]

for the independent events A and B, Pr(A) = 0.6 and Pr(A U B) = 0.8

Pr(B) is equal to...

trying to use the formula but it still confuses me.

[RKTR]

why is this wrong? 2013 exam 2 q

How come you got an extra -k? I tried with my calculator and got the same answer as the report.  I think they did area of triangle minus area under curve since  area under tangent is a triangle.

[RKTR]

for the independent events A and B, Pr(A) = 0.6 and Pr(A U B) = 0.8

Pr(B) is equal to...

trying to use the formula but it still confuses me.

Pr(A U B) = Pr(A) + Pr (B) - Pr(A n B)
For independent events, Pr(A n B) = Pr (A) x Pr (B)
0.8= 0.6 + Pr(B) - 0.6 Pr(B)
0.2=0.4Pr(B)
Pr(B) = 0.5

[Brunette15]

Can someone please help explain the theory to part b)iii) of this question? I don't really understand the explanation on vcaa...

[BLACKCATT]

Can someone please help explain the theory to part b)iii) of this question? I don't really understand the explanation on vcaa...

If you sketch the derivative of the function, you'll see that it will never equal zero, hence there can never be any stationary points for f(x)

[Valyria]

2007 Exam 2 5fii) How do we know to use from 20 to 30?

2011 Exam 2 4f) Why do we want dT/dx to be less than or equal to zero?

Thanks

2007; The circuit has 2 components, one between [10,20) and [20,30]. If you try use [10,20) to determine the value of b for which this maximum occurs, you are negating the other component of the circuit. Thus, the 2nd part of the function, between [20,30], must be in your calculations.

2011; At dT/dx=0, Tazzy will reach the plant at the minimum time. However, as the function is decreasing, when dT/dx<0, k won't return a local minimum but rather, an absolute minimum for the graph.

[Jason12]

0.8= 0.6 + Pr(B) - 0.6 Pr(B)
0.2=0.4Pr(B)

what happened between these steps? i.e. How did it become 0.4Pr(B)?