VCE Methods Question Thread!

[Zues]

oh thats weird then, all the questions i used my way of doing it and yielded the same answer.

my notes, given by teacher, says that vertical asymptotes are found by finding a value x that results in the denominator = 0

and the oblique asymptote is the remainder of the expression, ignoring the functional part of the expression.

[SE_JM]

Does anyone have modulus worksheets on logarithms and exponentials?

[keltingmeith]

Does anyone have modulus worksheets on logarithms and exponentials?

The idea behind them is just like with polynomial/linear functions. Any particular reason you want them for just logarithms/exponentials?

[cosine]

The idea behind them is just like with polynomial/linear functions. Any particular reason you want them for just logarithms/exponentials?

Euler my friend (or anyone else lol) you got some log worksheets or anything useful i can find online to practice? Cheers buddy!

[SE_JM]

Hello!
This is because I want some more practice done
I got this question on a test: graph y= |e^x-k|, given that k>0

and I could do it but still didn't feel comfortable with it. I looked for some worksheets online but couldn't find any on logs and exponentials so I asked just in case someone has some and is nice enough to share

[Orb]

Where am i going wrong 
 Solve for x











)

If you look closely, your first three steps lead back to the same -x+2= ln(x)
And also, xln(1) does not equal ln(x), simply because ln(1) = 0, so that's effectively saying 0 = ln(x)

^that's probably the misconception where you ended up solving it incorrectly

[SE_JM]

If you look closely, your first three steps lead back to the same -x+2= ln(x)
And also, xln(1) does not equal ln(x), simply because ln(1) = 0, so that's effectively saying 0 = ln(x)

^that's probably the misconception where you ended up solving it incorrectly

on your 6th step, you said:
2=x(log_e1+1)
I think this is where you were wrong.
Firstly, you can't take a factor of x from log_ex. For you to take a factor of a number from a log, the number should be in front of the log. e.g. 2log_e4.
in this case, you could take a factor of 2, but not 4. This is because 4 is the VALUE of the log.

That's why you cannot take a factor of x from log_ex because x is not a factor of the log, it's the value of the log.
 I hope I made sense

[SE_JM]

lol I know that feeling

Absolute legend! Thank you, I can definitely say this question raised my temper, lol...

have you solved for x yet? I can't solve it

[cosine]

lol I know that feeling :Phave you solved for x yet? I can't solve it

This is a calculator question, but i just wanted to know why my method wasnt working!

[SE_JM]

that's reassuring

This is a calculator question, but i just wanted to know why my method wasnt working!

[knightrider]

Why does the cas write as how does the cas get this?

[catherine_mimi]

-4(-x-2)
=(4x+8)
= 4(x+2)

Hope this helped!

[SE_JM]

Hello, I have a question on finding a derivative of this function.
The question asks:
find the derivative of each of the following with respect to x, using the product rule:
x²(x²+2x)^(1/3)

I keep getting the wrong answer, which is:
(2x²(4x+7))/(3((x²+2x)²)^(1/3))
please help

[Orb]

on your 6th step, you said:
2=x(log_e1+1)
I think this is where you were wrong.
Firstly, you can't take a factor of x from log_ex. For you to take a factor of a number from a log, the number should be in front of the log. e.g. 2log_e4.
in this case, you could take a factor of 2, but not 4. This is because 4 is the VALUE of the log.

That's why you cannot take a factor of x from log_ex because x is not a factor of the log, it's the value of the log.
 I hope I made sense

Yeah probably made more sense than me

[keltingmeith]

Hello, I have a question on finding a derivative of this function.
The question asks:
find the derivative of each of the following with respect to x, using the product rule:
x²(x²+2x)^(1/3)

I keep getting the wrong answer, which is:
(2x²(4x+7))/(3((x²+2x)²)^(1/3))
please help

Is that the answer you keep getting, or is that the answer they supplied? Because that doesn't make sense as an answer, and I'm almost certain is wrong.