VCE Methods Question Thread!

[Fishyiscool]

I know this is a stupid question but how do you find the asymptotes of a tan graph? :S i dont understand the logic behind it.

[Hutchoo]

b^3...
Have my babies.

[brightsky]

I know this is a stupid question but how do you find the asymptotes of a tan graph? :S i dont understand the logic behind it.

tan(x) = sin(x)/cos(x). so tan(x) has a vertical asymptote whenever cos(x) = 0.

[leejieun94]

I know this is a stupid question but how do you find the asymptotes of a tan graph? :S i dont understand the logic behind it.

it's not a stupid question lol
the easy way in doing so is letting the denominator of a tan function equal to 0
by using such method, you can find the equations of asymptotes

edit: yeh what brightsky said

[Hutchoo]

NEVERMIND  GOT IT

[Hutchoo]

Help required

[Shenz0r]

f(x) = 2x+1/5x+3 = 2/5 + 1/5(5x+3) (long division)
swap x & y
x = 2/5 + 1/5(5y+3)
x - 2/5 = 1/5(5y+3)
5(5y+3) = 1/(x-2/5)
5y+3 = 1/(5x-2)
5y = 1/(5x-2) - 3
y = 1/(25x-10) - 3/5
Range: R\{-3/5}
Domain: R\{2/5}

[Phy124]

f(x) = 2x+1/5x+3 = 2/5 + 1/5(5x+3) (long division)
swap x & y
x = 2/5 + 1/5(5y+3)
x - 2/5 = 1/5(5y+3)
5(5y+3) = 1/(x-2/5)
5y+3 = 1/(5x-2)
5y = 1/(5x-2) - 3
y = 1/(25x-10) - 3/5
Range: R\{-3/5}
Domain: R\{2/5}

Just an alternate method to avoid long division for anyone interested.

For inverse swap x and y;















For domain, solve denominator to equal 0, this will be the asymptote;





Therefore domain: R\{}

For range, range inverse is equal to domain original;

Therefore range: R\{}

[Hutchoo]

Haha, thank you guys so much!

That question was on my SAC today.

[mpathy]

Hey sorry if this is a stupid question.

How do I find the equivalent angle for cos (x) = -0.6591?

In the worked example it says it is 0.8512, but I have no idea how they get it

[pi]

Type in and make sure your mode is radians

[mpathy]

Thanks dude appreciate it. Took me a while to change into radians but I finally done it, come at me end of year exams.

[Hutchoo]

Thanks dude appreciate it. Took me a while to change into radians but I finally done it, come at me end of year exams.

Calm down. There's 3 terms left xD

[mpathy]

Thanks dude appreciate it. Took me a while to change into radians but I finally done it, come at me end of year exams.

Calm down. There's 3 terms left xD

yer man i know, but I have a feeling I'm gonna ace it because I know how to change into radians on calc now

/sarcasm

[Insa]

Hey guys,

Can anyone help me find the x-intercepts to his equation. I'm trouble solving this. Thank you.