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April 18, 2026, 05:01:21 am

Author Topic: VCE Methods Question Thread!  (Read 6028841 times)  Share 

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monkeywantsabanana

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Re: VCE Methods Question Thread!
« Reply #600 on: May 10, 2012, 07:23:10 pm »
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Consider the graph y=xe^x

Is it correct to say that there's an asymptote at y=0? or do you have to say that y=0 for values of x<0?


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pi

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Re: VCE Methods Question Thread!
« Reply #601 on: May 10, 2012, 07:25:03 pm »
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I think saying y=0 (ie. when labeling the asymptote on a sketched graph) is sufficient at a Methods level, as the latter is implied :)

Kelui

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Re: VCE Methods Question Thread!
« Reply #602 on: May 10, 2012, 08:10:45 pm »
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Any idea?

"Use the following data to create a polynomial that will model the information given.

1) f(-1)=0 and f(4)=0

a. f'(2)=0 and f'(x)>0 for x<2 and f'(x)<0 for x>2 -(not sure if that is the right order)

Sketch a simple graph that will model the information above. (3 marks)"
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Phy124

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Re: VCE Methods Question Thread!
« Reply #603 on: May 11, 2012, 04:07:21 pm »
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f(-1)=0
Is this supposed to be f(0)=0
f(4)=0
Or alternatively, this f(5)=0, by any chance?

It appears they are looking for a negative parabola with a turning point in the positive part of the y axis, but unfortunately this can't be done with the information given, as the turning point won't be halfway between the x-intercepts.
« Last Edit: May 11, 2012, 04:10:02 pm by ~My♥Little♥Pony~ »
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breadkay

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Re: VCE Methods Question Thread!
« Reply #604 on: May 12, 2012, 11:51:35 pm »
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Just wondering what is the best way to solve an equation like:


kamil9876

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Re: VCE Methods Question Thread!
« Reply #605 on: May 12, 2012, 11:57:03 pm »
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Let and then you really want to solve



Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

pi

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Re: VCE Methods Question Thread!
« Reply #606 on: May 12, 2012, 11:57:36 pm »
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Just wondering what is the best way to solve an equation like:



  (times both sides by )

Let




edit: beaten...

Yep, you can do the rest

breadkay

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Re: VCE Methods Question Thread!
« Reply #607 on: May 13, 2012, 12:03:48 am »
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Thank you, thank you!  ;D

I did the substitution method as above, but didn't think to multiply out :(

AutumnConcerto

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Re: VCE Methods Question Thread!
« Reply #608 on: May 13, 2012, 05:59:54 pm »
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I have a question regarding differentiating a modulus function!

lets just say f(x) = |x^2-1|

The textbook says that to differentiate this, you would define the function as:

f(x) = g(h(x)) where g(x) = |x| and h(x) = x^2-1, converting this into a composite function.

Then it says that by using the chain rule we can find the derivative of f(x) using the following formula:

f'(x) = g'(h(x))h'(x)
Its this part that I don't understand D:


Can anyone help out? Much appreciated ;D
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kamil9876

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Re: VCE Methods Question Thread!
« Reply #609 on: May 13, 2012, 06:09:27 pm »
+3
That is exactly the chain rule. Maybe not stated exactly as you know it.
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AutumnConcerto

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Re: VCE Methods Question Thread!
« Reply #610 on: May 13, 2012, 06:24:03 pm »
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That is exactly the chain rule. Maybe not stated exactly as you know it.

Yeah thats what I don't understand -.-
Can you briefly explain how it is the chain rule? D:
What I was taught is dy/dx = du/dx x dy/dx, I wasn't taught the Leibniz notation.
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Phy124

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Re: VCE Methods Question Thread!
« Reply #611 on: May 13, 2012, 07:10:20 pm »
+1
That is exactly the chain rule. Maybe not stated exactly as you know it.

Yeah thats what I don't understand -.-
Can you briefly explain how it is the chain rule? D:
What I was taught is dy/dx = du/dx x dy/dx, I wasn't taught the Leibniz notation.
Well you can do it using that notation but its a bit more messy IMO. (especially considering you might have to let , if you didn't already know the derivative of an absolute function)





^See this, if you don't understand why









Now to explain why , eh? <-- probably easier said than done :P

In reality what you have denoted as u is what the textbook has donated as h(x).

Lets say we had,

1.

2.

3.

4.

5.

Alternatively...



Make this

1.

2.

3.

4.

5.

Not sure you'll understand that, but hey, worth a shot :P
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AutumnConcerto

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Re: VCE Methods Question Thread!
« Reply #612 on: May 13, 2012, 07:20:21 pm »
0
That cleared up everything, thanks so much!
You were very concise so yeah i understood :)
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dinosaur93

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Re: VCE Methods Question Thread!
« Reply #613 on: May 14, 2012, 08:14:44 pm »
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can someone be kind enough to help me walk through these questions? tnx heaps~!



Q1 c and d,
How do you show that one grpah touches the other?



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Re: VCE Methods Question Thread!
« Reply #614 on: May 15, 2012, 05:27:18 pm »
0
Let y=n be a power function where n is a whole positive number, use calculus to find which values of n there is a local minimum of the function..

Don't really know how to approach this question.. do I just sub in a random positive number and then use calculus to find the stationary points and then the local minimum?

Please help.. please show all working out..


2)a) Consider the power function x2/3 which is assumed to have relationship x2/3=(x1/3)2 and this applies to all fractional indices

(i) Use calculus to show that the minimum of this function is a cusp and state its coordinates. (In this answer you expected to provide a definition of a cusp)

b) Consider y=x4/3
i) Use calculus to investigate its minimum. Is it a local minimum or a cusp and state its coordinates.