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March 15, 2026, 05:44:39 am

Author Topic: VCE Methods Question Thread!  (Read 5969924 times)  Share 

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Hutchoo

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Re: VCE Methods Question Thread!
« Reply #720 on: July 11, 2012, 12:02:20 am »
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OH, I get what I did wrong now! I didn't add the + c so my workings got pretty confusing :/

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breadkay

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Re: VCE Methods Question Thread!
« Reply #721 on: July 12, 2012, 03:30:44 pm »
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Hi,

I am struggling to understand this question:
Quote
Find the acute angle of intersection between x=2, y=x^2

brightsky

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Re: VCE Methods Question Thread!
« Reply #722 on: July 12, 2012, 05:08:02 pm »
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At x=2, dy/dx = 2(2) = 4.
so tan(theta) = 1/4
theta = arctan(1/4) = 14.03 degrees

Tip: Draw the graph and don't rely on formulas.
« Last Edit: July 12, 2012, 05:10:32 pm by brightsky »
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soccerboi

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Re: VCE Methods Question Thread!
« Reply #723 on: July 12, 2012, 06:04:37 pm »
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Can someone help me with this?

The graph of afunction f lies above the x axis for [0,2] and integral from 0 to 2 f(x)dx=6. The graph of f is dilated by a factor of 0.5 from the x axis, then translated 4 units up. Find the area enclosed by the graph, coordinate axes and the line x=2.

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brightsky

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Re: VCE Methods Question Thread!
« Reply #724 on: July 12, 2012, 06:26:42 pm »
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Area = int^(2)_(0) (0.5 f(x) + 4) dx
= 0.5 int^(2)_(0) f(x) dx + int^(2)_(0) 4 dx
= 0.5*6 + [4x]^(2)_(0)
= 3 + 8
= 11 units^2
hopefully that corresponds with the answer you have.
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breadkay

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Re: VCE Methods Question Thread!
« Reply #725 on: July 13, 2012, 03:00:02 pm »
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At x=2, dy/dx = 2(2) = 4.
so tan(theta) = 1/4
theta = arctan(1/4) = 14.03 degrees

Tip: Draw the graph and don't rely on formulas.

Why is it 1/4 and not 4?

Phy124

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Re: VCE Methods Question Thread!
« Reply #726 on: July 13, 2012, 03:59:18 pm »
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At x=2, dy/dx = 2(2) = 4.
so tan(theta) = 1/4
theta = arctan(1/4) = 14.03 degrees

Tip: Draw the graph and don't rely on formulas.

Why is it 1/4 and not 4?
arctan(4) would give the obtuse angle as the θ in m=tan(θ) is the angle between the line and the horizontal.

If you wanted to use arctan(4) you will have to subtract the given angle from 90°
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breadkay

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Re: VCE Methods Question Thread!
« Reply #727 on: July 16, 2012, 06:27:28 pm »
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Another question  :-[

How does this work?

b^3

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Re: VCE Methods Question Thread!
« Reply #728 on: July 16, 2012, 06:35:40 pm »
+1
I probably wouldn't show all the steps below but this should help you get your head around it :)
« Last Edit: July 16, 2012, 06:37:21 pm by b^3 »
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breadkay

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Re: VCE Methods Question Thread!
« Reply #729 on: July 16, 2012, 06:43:56 pm »
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Thank you!!!!  :D :D :D

ldee

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Re: VCE Methods Question Thread!
« Reply #730 on: July 16, 2012, 09:02:52 pm »
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This is another question like the one a few above, but I cant understand it!

Find the acute angle of intersection of the curves y=sin(2x) and y=cox(x) at the point (pi/2, 0)..

So I found the derivatives of each of the equations to be -2 and -1 at the particular point, but where to go from here?

The worked solutions uses a formula tan(a) = ((-1)-(-2)) / (1+(-1)(-2))... But I've never seen this before, can somebody please explain to me how it works?

brightsky

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Re: VCE Methods Question Thread!
« Reply #731 on: July 16, 2012, 09:09:23 pm »
+1
draw the diagram/graph. let a and b be the angle the tangents to y=sin(2x) and y = cos(x) at x = pi/2 make with the negative direction of the x-axis respectively. it is clear that the required acute angle is given by a-b.
now tan a = 2 and tan b = 1. so a - b = arctan(2) - arctan(1) = arctan(2) - pi/4.

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Phy124

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Re: VCE Methods Question Thread!
« Reply #732 on: July 16, 2012, 09:15:53 pm »
+1
They used the formula for the angle between two lines with gradients and



Alternatively you can work out the angles to the horizontal individually and add/subtract them to give the angle between the lines.
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Re: VCE Methods Question Thread!
« Reply #733 on: July 17, 2012, 07:22:09 pm »
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Could someone explain how to do this question:
A spinner has three equally likely sectors numbered from 1 to 3.
Find Pr(X=2 | X≠1)
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Re: VCE Methods Question Thread!
« Reply #734 on: July 17, 2012, 07:27:23 pm »
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Could someone explain how to do this question:
A spinner has three equally likely sectors numbered from 1 to 3.
Find Pr(X=2 | X≠1)
What did the question define the random variable X as?

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