VCE Methods Question Thread!

[ahat]

Ohh....I'm doing MAV 2013 Exam 1 tomorrow.

Yeah, I do agree with you there about difficulty. I guess its good though, just in case VCAA give us a hard paper (Means that we are fully prepared). Even the 2013 Heffernan paper was pretty hard to be honest.

Should this be telling us something? 

[shadows]

Should this be telling us something? 

Haha, VCAA exams are getting harder.

We will have to wait and see on Wednesday.

[Damoz.G]

Should this be telling us something? 

Yes, as shadows said, VCAA Exams are getting harder.

Thankfully it will be all over for me in less than a week and a half. PUMPED!

[Flor]

Could someone help me identify where I've gone wrong in this question? It's the 2006 exam 1 question 6. My working: http://oi40.tinypic.com/2ljnjer.jpg
http://oi41.tinypic.com/rjmb83.jpg

[Lejn]

Could someone help me identify where I've gone wrong in this question? It's the 2006 exam 1 question 6. My working: http://oi40.tinypic.com/2ljnjer.jpg
http://oi41.tinypic.com/rjmb83.jpg

15/24 - 25/24 = -10/24, not 10/24.

third last line.

[Nato]

this is a 1/2 question.

how many odd numbers greater than 3000 can be made using the digits 2,4,5,7. (can only use them once)

[b^3]

Since it has to be greater than 3000, and we have 4 digits, we have to use all of the 4 digits.
Lets starts off by with 4 blank boxes. The numbers we put in the boxes will be the number of options in that position.

-----  -----  -----   ----- 
|   |   |   |   |   |    |   |   
-----  -----   -----  ----- 

Firstly we will look at our two restrictions.
Now for it to be greater than 3000, the first digit has to be either 4,5 or 7, so we have three options.
-----  -----  -----   ----- 
| 3 |  |   |   |   |    |   |   
-----  -----   -----  ----- 
Now for the number to be odd, the last digit has to be an odd number, this is where the situation splits. If the first digit was odd then the first digit only had two options we will only have 1 option left, if the first digit was even (meaning it had 1 option, as it has to be the 4) then we have 2 options left, the 5 or 7.
So we have two situations.
 -----  -----  -----   -----                    -----  -----  -----   -----
| 2 |  |   |   |   |    | 1 |                    | 1 |  |   |   |   |    | 2 |
-----  -----   -----  -----                     -----  -----   -----  -----

Now for the two middle numbers, for the first option we have two digits left, and once we use one of those we will only have 1 left. So we have a 2 and a 1. 
 -----  -----  -----   -----                    -----  -----  -----   -----
| 2 |  | 2 |   | 1 |    | 1 |                  | 1 |  | 2 |  | 1 |    | 2 |
-----  -----   -----  -----                     -----  -----   -----  -----
So the number of options is

Spoiler

And to check the answer I went through the options, not the best idea but to be sure
4275
4725
4257
4527
5247
5427
7245
7425

Hope that helps, there's probably a simpler way of doing it though.

[rhinwarr]

This is from MAV 2011. I'm stuck on part ii

[clueless123]

because top part is the differential thing of the bottom part
+c

[sasa]

for inv. functions, do we always need to state the dom and range even if the question does not ask for it?

[Damoz.G]

for inv. functions, do we always need to state the dom and range even if the question does not ask for it?

If it doesn't ask for the Range, then don't worry.

However, you should always give the Domain.

[zvezda]

Do you guys think a pacer or a pen should be used tomorrow?
Cheers

[Damoz.G]

Do you guys think a pacer or a pen should be used tomorrow?
Cheers

I'm using a pen because I'm used to it now from doing Trial Exams because one of the teachers told us to.

But a pacer is completely fine as well.

[zvezda]

Im just worried that my working may get smudged or something or may fade out before somebody marks it..
Thanks guys

[Sanguinne]

can someone explain how to do q4e and 4f in detail in vcaa exam 2 2012?