1. Find an expression for the surface area of the can (two circles and a cylinder that is rolled out with length equal to the perimeter of the circle).
2. You need to get the SA in terms of one variable only, so you need either

in terms of

or

in terms of

. To do this you can use the piece of information for the volume of the can, equate that and rearrange for one of the variables.
3. Substitute this variable back into your expression for the SA area so that it is in terms of one variable only.
4. Do a quick sketch to make sure the minimum is at a turning point.
5. Differentiate your expression for the surface area and equate to zero, find the value of the variable you choose.
6. Substitute this back into the other expression to find the other dimension.
7. State the dimensions of the can for minimum material.
(8. Not required but you could then use this to find the amount of material that would be used)