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April 28, 2026, 04:19:15 am

Author Topic: VCE Methods Question Thread!  (Read 6061495 times)  Share 

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Adiamond

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Re: VCE Methods Question Thread!
« Reply #11970 on: September 03, 2015, 04:32:08 pm »
+1
Can anyone please check my working out and answer for this question?

Thanks  :)

Looks fine to me.

teganlongworth

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Re: VCE Methods Question Thread!
« Reply #11971 on: September 03, 2015, 05:55:30 pm »
0
Please help me with this continuous random probability question! SEE PICTURE ATTACHED! Thankyou ;D

warya

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Re: VCE Methods Question Thread!
« Reply #11972 on: September 03, 2015, 06:46:25 pm »
+1
Please help me with this continuous random probability question! SEE PICTURE ATTACHED! Thankyou ;D

Cas assisted right? Define as a hybrid function on your calculator then antidiff x*g(x) within the specified domain for the mean.
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odeaa

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Re: VCE Methods Question Thread!
« Reply #11973 on: September 04, 2015, 02:46:33 pm »
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Consider the family of functions where and is a real constant and .

For any one set of graphs of and , how many possible solutions are there to ?

Have never seen the subscript notation before. From MAV Exam 2 2012
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Orb

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Re: VCE Methods Question Thread!
« Reply #11974 on: September 04, 2015, 05:17:13 pm »
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Consider the family of functions where and is a real constant and .

For any one set of graphs of and , how many possible solutions are there to ?

Have never seen the subscript notation before. From MAV Exam 2 2012

Just the same thing as f(x) i believe
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qwerty101

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Re: VCE Methods Question Thread!
« Reply #11975 on: September 04, 2015, 08:19:50 pm »
0
help on this one please,

ans: 0.04

qwerty101

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Re: VCE Methods Question Thread!
« Reply #11976 on: September 04, 2015, 08:40:25 pm »
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Also confused with this one. to find median

i know that median is the value at which the area of the pdf =1/2, however in their solution they have found medium using the 2nd equation where x is between 5 and 15 to find the median.

I would've thought that you find the area under the first equation which is 1/3 then gone

1/3 + (what they did in solution) = 1/2 , so it takes into account the whole pdf? thanks

qwerty101

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Re: VCE Methods Question Thread!
« Reply #11977 on: September 04, 2015, 08:54:33 pm »
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sorry for the questions, also this one.

Why between 0 and 11, and say not 15 and 4 ?

thanks

StupidProdigy

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Re: VCE Methods Question Thread!
« Reply #11978 on: September 04, 2015, 08:54:48 pm »
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Also confused with this one. to find median

i know that median is the value at which the area of the pdf =1/2, however in their solution they have found medium using the 2nd equation where x is between 5 and 15 to find the median.

I would've thought that you find the area under the first equation which is 1/3 then gone

1/3 + (what they did in solution) = 1/2 , so it takes into account the whole pdf? thanks
Yes that's right. You need to consider the area of the first part of the hybrid which usually is <1/2 in these types of questions and then set the second hybrid integral equal to 1/2-first integral value
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qwerty101

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Re: VCE Methods Question Thread!
« Reply #11979 on: September 05, 2015, 11:19:03 am »
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thanks for that!!

im still stuck on the one with pr (0 < x < 11) and the question about the cards!

thanks
« Last Edit: September 05, 2015, 11:22:18 am by qwerty101 »

qwerty101

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Re: VCE Methods Question Thread!
« Reply #11980 on: September 05, 2015, 04:35:00 pm »
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wondering why Pr(a) = Pr(b) ?

since pr(a intersect b) does not necessarily equal pr (b intersect a) therefore they cant really cancel each other out.

keltingmeith

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Re: VCE Methods Question Thread!
« Reply #11981 on: September 05, 2015, 05:22:21 pm »
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wondering why Pr(a) = Pr(b) ?

since pr(a intersect b) does not necessarily equal pr (b intersect a) therefore they cant really cancel each other out.

No... They're equal. I suggest shading in the area on a venn diagram for further re-enforcement.

qwerty101

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Re: VCE Methods Question Thread!
« Reply #11982 on: September 06, 2015, 12:40:43 pm »
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No... They're equal. I suggest shading in the area on a venn diagram for further re-enforcement.

yeah that was pretty stupid on my behalf haha i get ya, dont know why i said that lol.

Orson

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Re: VCE Methods Question Thread!
« Reply #11983 on: September 06, 2015, 04:38:33 pm »
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How would you do this tech free? I don't see how the domain and range of f(x) are both [1, infinity)

Let f(x) = loge(x) and g(x) = x^2 + 1. Both functions have a maximal domain. Find the range of the function h = f(g(x))

Are these rules true?
dom h = ran f, ran h = dom f

Thanks!
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keltingmeith

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Re: VCE Methods Question Thread!
« Reply #11984 on: September 06, 2015, 05:02:42 pm »
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How would you do this tech free? I don't see how the domain and range of f(x) are both [1, infinity)

Let f(x) = loge(x) and g(x) = x^2 + 1. Both functions have a maximal domain. Find the range of the function h = f(g(x))

Are these rules true?
dom h = ran f, ran h = dom f

Thanks!

Nope - the domain of h is the domain of g. The range is a bit more interesting, see if you can find a way to determine it (hint: it is related to the range of f)