VCE Specialist 3/4 Question Thread!

[cosine]

can someone also please work it out

I havent done this topic but from basic functions, i guess transpose for y first?






I dont even know what im doing lol, someone please help...

[keltingmeith]

why have they said a is square root 3 on 2, as apposed to square root 2

For a hyperbola with equation , it has asymptotes at

For your hyperbola, we have equation . Notice how it's not in the form of the above?

So, we change it to suit, giving us , so

I havent done this topic but from basic functions, i guess transpose for y first?






I dont even know what im doing lol, someone please help...

Yeah... Maybe don't play with questions you haven't seen the theory for.

[Zues]

lol bit of a stupid question, my brains not working haha.

why do the expressions / bracket thing join together in the denominator

[cosine]

For a hyperbola with equation , it has asymptotes at

For your hyperbola, we have equation . Notice how it's not in the form of the above?

So, we change it to suit, giving us , so
Yeah... Maybe don't play with questions you haven't seen the theory for.

Mate you are a genius, you answer every question lol!
Yeah, lesson learnt. Im to keen to answer questions, just wanna help, you know?

[cosine]

lol bit of a stupid question, my brains not working haha.

why do the expressions / bracket thing join together in the denominator

Okay i do know this, its because the two bottom denominators always multiply with each other when you are adding/subtracting fractions, and when you multiply more than one term with another, there are always brackets. So this means you can expand the two brackets, or you can leave them factorised, which is the preferred way.

[Zues]

oh right, i times everything in the first bracket by (x-1) and so on lol such a stupid question

[cosine]

oh right, i times everything in the first bracket by (x-1) and so on lol such a stupid question

Its good, you just need a break!

[Zues]

For a hyperbola with equation , it has asymptotes at

For your hyperbola, we have equation . Notice how it's not in the form of the above?

So, we change it to suit, giving us , so
Yeah... Maybe don't play with questions you haven't seen the theory for.

how do you just bring the 2 to the denominator?

and how do you know you had to square the denominators, dont we always assume there squared, when do e know when to do so? nearly makes sense

[Talia2144]

Hi, sorry for posting this message in this forum but I was wondering if anyone can tell me where can I find or buy books or pdf file based on, how to use the functions of Cas calculator beside having it in the textbook. Thank you

[DSubShell]

Hi, sorry for posting this message in this forum but I was wondering if anyone can tell me where can I find or buy books or pdf file based on, how to use the functions of Cas calculator beside having it in the textbook. Thank you

Here's a really handy guide by a forum member (b^3) specifically suited for Spesh Maths:
http://www.atarnotes.com/?p=notes&a=feedback&id=661

Just download the PDF file. It gives you all sorts of handy tip and tricks

[keltingmeith]

Here's a really handy guide by a forum member (b^3) specifically suited for Spesh Maths:
http://www.atarnotes.com/?p=notes&a=feedback&id=661

Just download the PDF file. It gives you all sorts of handy tip and tricks

Note: This is for the TI-nspire. If you are using the Classpad, this will not be helpful for you.

[Zues]

why is there an asymptope at y = g(x)

[Zues]

why does the graph touch the asymptope

[theshunpo]

why does the graph touch the asymptope

That isn't the asymptote, it's the graph of .

Edit: I guess it gives you an idea of the addition of ordinates

[cosine]

why is there an asymptope at y = g(x)

is always the y asymptote, also known as the horizontal asymptote (as it goes through the y-axis, making it horizontal)

The graph will approach x=0 but never touch the y asymptote, hence why the range is always
R\{g(x)} meaning the range consists of all real numbers, besides the y asymptote, g(x).

However, different books display different forms. My book's standard hyperbola equation is where k is the horizontal (y) asymptote.

Hope this helped!