Login

Welcome, Guest. Please login or register.

July 17, 2026, 11:13:14 pm

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2812583 times)  Share 

0 Members and 6 Guests are viewing this topic.

Sine

  • Werewolf
  • National Moderator
  • Great Wonder of ATAR Notes
  • *****
  • Posts: 5132
  • Respect: +2103
Re: Specialist 3/4 Question Thread!
« Reply #8475 on: January 06, 2017, 09:14:44 pm »
+2
Where can I buy the worked solutions for the textbook?
Your teacher should have them avaliable to you

Need help with Q1 and Q2b: http://m.imgur.com/1rRQsZg

For Q1) I got the answer correct but had to guess one step which I still don't understand. I made cos(3t) and sin(3t) the subject, since the equation for a circle is sint squared + cost squared = 1, how does squaring cos3t and sin3t allow me to still get the correct answer?

Q2b) The answer has x = 4 but didn't show their method. I subbed the points and solved for the gradient which is undefined. How would I show that the line is x=4 mathematically?

Thanks
sint squared + cost squared = 1 so t is any angle in this case it is 3t (which is still an angle) since cos and sin have the same angle each of them squared sums to 1
 for 2(b) your working is fine imo. Gradient undinfied + passes through (4,y) is sufficient

peter761

  • Fresh Poster
  • *
  • Posts: 2
  • Respect: 0
  • School: sktdmfmvf
  • School Grad Year: 2007
Re: Specialist 3/4 Question Thread!
« Reply #8476 on: January 06, 2017, 11:28:08 pm »
0
Hey, does anyone mind helping me out with question 2b and 3b. Greatly appreciated.

peanut

  • Forum Regular
  • **
  • Posts: 89
  • Respect: +1
Re: Specialist 3/4 Question Thread!
« Reply #8477 on: January 06, 2017, 11:32:32 pm »
+1
Hey, does anyone mind helping me out with question 2b and 3b. Greatly appreciated.
2b) Find the magnitude of vector b and multiply that by the unit vector of a.

nyggfany

  • Adventurer
  • *
  • Posts: 14
  • Respect: 0
Re: Specialist 3/4 Question Thread!
« Reply #8478 on: January 07, 2017, 01:39:11 am »
+2

Hey, does anyone mind helping me out with question 2b and 3b. Greatly appreciated.

Quantum44

  • Victorian
  • Forum Leader
  • ****
  • Posts: 756
  • Respect: +313
Re: Specialist 3/4 Question Thread!
« Reply #8479 on: January 08, 2017, 11:10:33 am »
0
Can someone help me with 6b and 6c? I managed to do them but the answers I got were different to the textbook answers so I must have screwed up my method somewhere.
UAdel MBBS

nyggfany

  • Adventurer
  • *
  • Posts: 14
  • Respect: 0
Re: Specialist 3/4 Question Thread!
« Reply #8480 on: January 08, 2017, 11:15:44 am »
+3

Can someone help me with 6b and 6c? I managed to do them but the answers I got were different to the textbook answers so I must have screwed up my method somewhere.

strawberry7898

  • Victorian
  • Trailblazer
  • *
  • Posts: 31
  • Respect: +5
Re: Specialist 3/4 Question Thread!
« Reply #8481 on: January 08, 2017, 06:45:13 pm »
0
Help with 8b please, answer is 7.1m/s not sure how to get there, answer to part a) was 4m/s^2 which I got correct. Question is attached  :)

keltingmeith

  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 5493
  • he/him - they is also fine
  • Respect: +1292
Re: Specialist 3/4 Question Thread!
« Reply #8482 on: January 08, 2017, 07:05:41 pm »
+2
Help with 8b please, answer is 7.1m/s not sure how to get there, answer to part a) was 4m/s^2 which I got correct. Question is attached  :)

What did you try? We might be able to show you where you went wrong instead of just giving an answer.

wyzard

  • Forum Obsessive
  • ***
  • Posts: 237
  • Respect: +42
Re: Specialist 3/4 Question Thread!
« Reply #8483 on: January 08, 2017, 07:09:12 pm »
+2
Help with 8b please, answer is 7.1m/s not sure how to get there, answer to part a) was 4m/s^2 which I got correct. Question is attached  :)

For maximum speed, we are assuming the box is travelling at it's terminal constant velocity where the forward force pushing the box is equal to resistance and the air resistance.

The amount of air resistance is then 3N, which you can use to evaluate the speed :P
Graduated from high school in 2012 with atar of 99.55.

Currently doing MSc in Physics at UoM researching on Quantum Computers.

Offering group lessons for Unit 3/4 VCE Methods and Physics for 2017!

Selling awesome and in-depth study notes for Unit 3 Physics, PM me if interested! :D

Writer/Tutor at (Nerd of Passion)!
Connect with me on Facebook!

Syndicate

  • Forum Leader
  • ****
  • Posts: 797
  • Hard work beats Talent
  • Respect: +139
Re: Specialist 3/4 Question Thread!
« Reply #8484 on: January 08, 2017, 07:10:43 pm »
+1
Help with 8b please, answer is 7.1m/s not sure how to get there, answer to part a) was 4m/s^2 which I got correct. Question is attached  :)

Got beaten... but here's the answer.

Answer
The object will be at its terminal velocity when Fnet = 0 N. Therefore 4.5 = 1.5 + kv^2.

EDIT:: Like Euler said, it would be better if you post your working out first, and then understand where you went wrong (which is the reason why I put my working out in spoilers)
« Last Edit: January 08, 2017, 07:12:59 pm by Syndicate »
2017: Chemistry | Physics | English | Specialist Mathematics | Mathematics Methods
2018-2020 : Bachelor of Biomedicine at University of Melbourne

Physics Guide 2017

Mattjbr2

  • Trendsetter
  • **
  • Posts: 165
  • Respect: +5
Re: Specialist 3/4 Question Thread!
« Reply #8485 on: January 14, 2017, 01:08:28 pm »
0
Hey guys :)
Can someone please tell me which step is incorrect? To me, it seems pretty straightforward and basic. But I keep getting the incorrect answer at the end :( I know that an easier method is possible - i.e.: line 1: sin2x*cos2x=(sinx*cosx)2 and so on - but in my specific method, where is my error? Sorry for no Latex! it's really difficult for me to write out equations that way   :-\

http://i.imgur.com/6Ek57fW.jpg
2017: Further (41)
2018: English Language - Specialist - Methods (40) - Chemistry
2019-2021: Biomedicine at Melbourne Uni

Insta: https://www.instagram.com/mattjbr2/

nyggfany

  • Adventurer
  • *
  • Posts: 14
  • Respect: 0
Re: Specialist 3/4 Question Thread!
« Reply #8486 on: January 14, 2017, 01:23:04 pm »
+1
Hey guys :)
Can someone please tell me which step is incorrect? To me, it seems pretty straightforward and basic. But I keep getting the incorrect answer at the end :( I know that an easier method is possible - i.e.: line 1: sin2x*cos2x=(sinx*cosx)2 and so on - but in my specific method, where is my error? Sorry for no Latex! it's really difficult for me to write out equations that way   :-\

http://i.imgur.com/6Ek57fW.jpg
Step 4 to 5, you've forgotten the 1/2 in front of cos2x

Mattjbr2

  • Trendsetter
  • **
  • Posts: 165
  • Respect: +5
Re: Specialist 3/4 Question Thread!
« Reply #8487 on: January 14, 2017, 01:26:45 pm »
+1
Step 4 to 5, you've forgotten the 1/2 in front of cos2x



thanks lol
2017: Further (41)
2018: English Language - Specialist - Methods (40) - Chemistry
2019-2021: Biomedicine at Melbourne Uni

Insta: https://www.instagram.com/mattjbr2/

manishmao

  • Adventurer
  • *
  • Posts: 18
  • Respect: 0
Re: Specialist 3/4 Question Thread!
« Reply #8488 on: January 14, 2017, 01:34:16 pm »
0
Any help with this question.

The triangular base ABC of a tetrahedron has side lengths AB=15, BC=12 and AC=9. The apex D is 9 cm vertically above C.

Find the angles that the sloping edges make with the horizontal.



Mattjbr2

  • Trendsetter
  • **
  • Posts: 165
  • Respect: +5
Re: Specialist 3/4 Question Thread!
« Reply #8489 on: January 14, 2017, 01:47:12 pm »
0
Any help with this question.

The triangular base ABC of a tetrahedron has side lengths AB=15, BC=12 and AC=9. The apex D is 9 cm vertically above C.

Find the angles that the sloping edges make with the horizontal.

If I understood the question correctly..
2017: Further (41)
2018: English Language - Specialist - Methods (40) - Chemistry
2019-2021: Biomedicine at Melbourne Uni

Insta: https://www.instagram.com/mattjbr2/