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August 22, 2025, 07:42:26 pm

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2579243 times)  Share 

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saba.ay

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Re: Specialist 3/4 Question Thread!
« Reply #1410 on: March 10, 2013, 06:36:38 pm »
0
How would I do the following?

cos^(-1)(tan(-pi/2))

(tan(-pi/2) gives undefined, but the answer is pi ? :/

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Re: Specialist 3/4 Question Thread!
« Reply #1411 on: March 10, 2013, 07:06:22 pm »
+1
It's undefined
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Re: Specialist 3/4 Question Thread!
« Reply #1412 on: March 10, 2013, 07:36:17 pm »
0

Could someone please explain this part.

Phy124

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Re: Specialist 3/4 Question Thread!
« Reply #1413 on: March 10, 2013, 07:46:08 pm »
+3
Could someone please explain this part.
I made a post about this sort of thing a while back, it might help:

Re: Specialist Question Thread!
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Re: Specialist 3/4 Question Thread!
« Reply #1414 on: March 10, 2013, 08:25:24 pm »
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I made a post about this sort of thing a while back, it might help:

Re: Specialist Question Thread!

Perfect, thanks :D

Would we be able to use that in the exam, or would we be expected to do something like let and solve provided and

lzxnl

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Re: Specialist 3/4 Question Thread!
« Reply #1415 on: March 10, 2013, 09:24:56 pm »
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The problem with introducing a square root is that you then introduce extra solutions. You'll have to check every solution you find at the end. Also, introducing a square root can make equations messier than they need to be.
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Re: Specialist 3/4 Question Thread!
« Reply #1416 on: March 10, 2013, 11:48:24 pm »
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I'm having trouble applying the double angle formula to find tan(pi/12), could someone please demonstrate? :)Thanks for helping!

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Re: Specialist 3/4 Question Thread!
« Reply #1417 on: March 10, 2013, 11:55:44 pm »
+4


Let



Let





http://www.wolframalpha.com/input/?i=tan(pi%2F12)

Solving this quadratic and taking the positive root (since tan(pi/12) > 0 since it's in the first quadrant).
« Last Edit: March 10, 2013, 11:58:16 pm by Hancock »
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Re: Specialist 3/4 Question Thread!
« Reply #1418 on: March 13, 2013, 08:37:50 pm »
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We just began Calculus in spesh and I'm unsure how to differentiate this using the chain rule

dy/dx=tan^4(2x)

EDIT:

I approached the question by doing this:
using dy/du = 4[]^3 and du/dx = 2 sec^2(2x)
4[tan(2x)]^3 x 2sec^2(2x) giving me the answer of 8 sec^2(2x) tan^3(2x)

I'm not sure that's right also, does the 8 apply to both the tan and the sec?

« Last Edit: March 13, 2013, 08:44:42 pm by Henreezy »
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Phy124

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Re: Specialist 3/4 Question Thread!
« Reply #1419 on: March 13, 2013, 08:46:01 pm »
+2
We just began Calculus in spesh and I'm unsure how to differentiate this using the chain rule

dy/dx=tan^4(2x)
Note that

Let and or whichever method you prefer.

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Re: Specialist 3/4 Question Thread!
« Reply #1420 on: March 13, 2013, 09:28:40 pm »
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I seem to be stuffing up every single differentiation of an an inverse circular function when there's a co-efficient in front. I'd really appreciate it to see the worked solution of the following question. It might help me determine where I'm going wrong. Thanks. :)

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Re: Specialist 3/4 Question Thread!
« Reply #1421 on: March 13, 2013, 09:32:39 pm »
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So basically, will I need to know this?


Phy124

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Re: Specialist 3/4 Question Thread!
« Reply #1422 on: March 13, 2013, 09:39:03 pm »
+2
I seem to be stuffing up every single differentiation of an an inverse circular function when there's a co-efficient in front. I'd really appreciate it to see the worked solution of the following question. It might help me determine where I'm going wrong. Thanks. :)

(Image removed from quote.)
Coefficients eh?

Remember that and you shouldn't have to many problems with them i.e. take it out the front at the start and draw some massive brackets around the rest of the expression :P

For the question at hand;

Let and





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Re: Specialist 3/4 Question Thread!
« Reply #1423 on: March 14, 2013, 02:54:50 pm »
0
Question 1:
How can I solve

x4 - 9x3 - 175x2 - 267x + 31050 = 0

algebraically WITHOUT using calculator?

Question 2: Set up simultaneous equations that could be used to find (-142 + 65i)^(1/3) in exact Cartesian form. Do not attempt to solve these equations.

Thanks
« Last Edit: March 14, 2013, 03:01:30 pm by Starfish »
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Re: Specialist 3/4 Question Thread!
« Reply #1424 on: March 14, 2013, 06:30:22 pm »
0
Factorise it; by letting x=random numbers, and hope that it =0. Which means its a factor.
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