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April 25, 2026, 02:39:50 am

Author Topic: Homework questions thread  (Read 178870 times)  Share 

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Aurelian

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Re: Holiday hw questions thread
« Reply #90 on: January 19, 2012, 11:51:16 pm »
0
Reason for the relationship between mass and energy required to stretch a bond is based on quantum theory, from memory.

huh?

Lol. Just ignore that, you don't need to worry about it :P

Thushan, I assume you are talking about how the intensity of the absorption band is directly proportional to the derivative of the molecular dipole moment (which is affected by the molecule's polarizability) in relation to the normal placement?

-_-
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Comatose

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Re: Holiday hw questions thread
« Reply #91 on: January 20, 2012, 02:36:09 pm »
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hey guys im having trouble with this question:
a precipitate of Fe2O3 of mass 1.43g was obtained by treating a 1.5L sample of bore water. What was the concentration of iron, in mol L-1 in the water?
cheers
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Kanon

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Re: Holiday hw questions thread
« Reply #92 on: January 20, 2012, 09:19:28 pm »
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Engage Panic Mode!
Could someone help me out with this one?

Quote
How many atoms are present in 5.00 mole of Copper Sulfate?
How I would have approached this was



However, the solutions have it as



Where'd the 6 come from in the solutions?
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jasoN-

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Re: Holiday hw questions thread
« Reply #93 on: January 20, 2012, 09:24:59 pm »
+1
^ CuSO4 contains 6 atoms per molecule
so 5 mols of CuSO4 contains 5*6.023E23 molecules

6 atoms : 1 molecule
x atoms : 5*6.023E23 molecules

x = 5*6.023E23*6 = 1.81E25
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Kanon

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Re: Holiday hw questions thread
« Reply #94 on: January 20, 2012, 09:29:40 pm »
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^ CuSO4 contains 6 atoms per molecule
so 5 mols of CuSO4 contains 5*6.023E23 molecules

6 atoms : 1 molecule
x atoms : 5*6.023E23 molecules

x = 5*6.023E23*6 = 1.81E25
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« Last Edit: January 20, 2012, 09:43:20 pm by Kanon »
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Aurelian

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Re: Holiday hw questions thread
« Reply #95 on: January 20, 2012, 09:35:41 pm »
+2
Engage Panic Mode!
Could someone help me out with this one?

Quote
How many atoms are present in 5.00 mole of Copper Sulfate?
How I would have approached this was



However, the solutions have it as



Where'd the 6 come from in the solutions?

Copper sulfate = CuSO4

There are 6 *atoms* in every molecule# of copper sulfate; hence, multiply by 6.

#nb, not actually really 'molecules' (ionic salt)
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Re: Holiday hw questions thread
« Reply #96 on: January 20, 2012, 09:45:43 pm »
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Thank you Aurelian :)
I'm stuck again haha, the next question asks
Quote
How many ions are present in 2.00 mole of Na3PO4?
I don't see any ions in that though? Would it be possible to say that we multiply it by 8 as there are 8 atoms per molecule ionic thingy?
I'm so sorry, i'm pretty bad at Chemistry.
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jasoN-

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Re: Holiday hw questions thread
« Reply #97 on: January 20, 2012, 09:58:55 pm »
+1
Ions in are (phosphate) and (sodium) ions
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KOM

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Re: Holiday hw questions thread
« Reply #98 on: January 21, 2012, 12:18:26 am »
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hey guys im having trouble with this question:
a precipitate of Fe2O3 of mass 1.43g was obtained by treating a 1.5L sample of bore water. What was the concentration of iron, in mol L-1 in the water?
cheers

You work out the mol of Fe2O3 and since there are 2 atoms of iron per Fe2O3 , n(Fe) = double of n(Fe2O3 )
From there, n(Fe)/1.5L will give you the concentration of Fe in mol L-1
« Last Edit: January 21, 2012, 12:20:02 am by KOM »
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soccerboi

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Re: Holiday hw questions thread
« Reply #99 on: January 21, 2012, 08:57:04 am »
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Hi guys, im stuck on this:

25cm^3 of a mixture of carbon monoxide and carbon dioxide were mixed with oxygen, which increaded the total volume to 55cm^3. When the mixture was exploded, the total volume was reduced to 50cm^3. Calculate the percentage by volume of carbon monoxide in the original mixture of carbon monoxide and carbon dioxide. Ans is 40%
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KOM

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Re: Holiday hw questions thread
« Reply #100 on: January 21, 2012, 07:18:27 pm »
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Hi guys, im stuck on this:

25cm^3 of a mixture of carbon monoxide and carbon dioxide were mixed with oxygen, which increaded the total volume to 55cm^3. When the mixture was exploded, the total volume was reduced to 50cm^3. Calculate the percentage by volume of carbon monoxide in the original mixture of carbon monoxide and carbon dioxide. Ans is 40%

I believe that you assume combustion between CO and O2
So 2CO + O2 --> 2CO2
so you have to lose 5cm^3 to have a total volume of 50cm^3, therefore 5cm^3 of the excess O2 is used up meaning 10cm^3 of CO was combusted, hence originally there was 10cm^3 of CO
10/25 = 0.4 = 40%

Hope that makes sense!
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soccerboi

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Re: Holiday hw questions thread
« Reply #101 on: January 21, 2012, 07:46:36 pm »
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Can you explain your thought process on how u derived the equation? I have trouble deriving equatoins for these types of questions.. Like, i dont understand how to know what are the products, what do u think about when u come up with equations for these types of questions?
« Last Edit: January 21, 2012, 09:13:45 pm by soccerboi »
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KOM

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Re: Holiday hw questions thread
« Reply #102 on: January 21, 2012, 10:51:06 pm »
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Can you explain your thought process on how u derived the equation? I have trouble deriving equatoins for these types of questions.. Like, i dont understand how to know what are the products, what do u think about when u come up with equations for these types of questions?

Well the mixture was exploded, so you'd assume a combustion reaction.
To combust something, you end up with carbon dioxide. So my thinking process was, ok, it shouldn't be a reactant then. Oxygen is always needed, so i wrote up CO + Oxygen --> Carbon Dioxide
and then I went from there
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soccerboi

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Re: Holiday hw questions thread
« Reply #103 on: January 21, 2012, 11:49:41 pm »
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Oh okay thanks alot, btw wouldnt H20 be a product of combustion or is it excluded in this case because it is an explosion?
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Panicmode

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Re: Holiday hw questions thread
« Reply #104 on: January 22, 2012, 01:57:18 am »
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Oh okay thanks alot, btw wouldnt H20 be a product of combustion or is it excluded in this case because it is an explosion?

Water cannot be a product as there was no hydrogen in any form in the tank. Water is usually formed when a hydrocarbon reacts because the hydrogen is able to react with oxygen to form water.

In this case, the only product possible would be carbon dioxide. 
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