Okay so Q3 in Neap 2007 says
Chromosome number is reduced during meiosis because the process involves
A. a single cell division without any chromosome replication
B. two cell divisions without any chromosome replication
C. two cell divisions in which chromosome replication occurs once
D. two cell divisions in which half of the chromosomes are destroyed.
The solutions said the answer is C. And their explanation was:
Meiosis involves two successive divisions, so A cannot be correct. At the very start of meiosis,
chromosomes in the parent cell replicate themselves into pairs of chromatids. B is therefore incorrect. In the
first division, each pair of homologous chromosomes is separated to reduce the chromosome number in the
daughter nuclei by half. In the second division, the pairs of chromatids separate and enter the daughter cells.
At no stage in the process are chromosomes destroyed.
So ^^^ it is saying that DNA replication occurs "at the very start of meiosis" ?
BUT THENNN
In Neap 2009 Q5:
Chromosome number is reduced during meiosis because the process consists of
A. two cell divisions without any chromosome replication
B. a single cell division without any chromosome replication
C. two cell divisions and only a single round of chromosome replication
D. four cell divisions and no chromosome replication
And the solutions say that the answer is A this time, with the explanation that:
Replication of DNA occurs during interphase and then the DNA coils to form the chromosomes. Each
chromosome is comprised of two identical chromatids. Meiosis consists of two divisions. The first separates
the chromosome pairs and the second division separates the chromatids.
So now what?