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April 28, 2026, 07:22:03 am
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Author Topic: Really easy Quick stoich help!  (Read 581 times)  Share 

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amilss

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Really easy Quick stoich help!
« on: March 04, 2012, 06:44:22 pm »
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Eg. H2SO4 + 2NaOH ------> Na2SO4 + h2O
So yeah i found that the NaOH is the limiting reactant (0.15 mol) 

And the question is to find the mass of sodium sulfate produced.

Im confused though because i thought you had to use the mol of the limiting reactant.

But you actually use the total mol of NaOH (0.30)




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Reckoner

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Re: Really easy Quick stoich help!
« Reply #1 on: March 04, 2012, 06:53:47 pm »
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What I think is that the 0.15mol of NaOH you found to be limiting was the amount of excess H2SO4. You use all of the limiting reagent, so in this case 0.30 mol. I think this is what you were looking for. Post the whole question then I can double check for you. 
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amilss

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Re: Really easy Quick stoich help!
« Reply #2 on: March 04, 2012, 06:57:44 pm »
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Nah it makes sense now- it limits the H2SO4, so Obviously all .30mol would be used to produce the sodium sulfate.

Thank you :)
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2011 - Psychology [42]
2012 atar aim - 99+. There,i said it, it's offical, now i have to reach it!
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