Author Topic: Completing the square complex numbers (Read 849 times) Tweet Share

kettles · « **on:** March 05, 2012, 07:11:37 pm »

hey guys, how would i factorise something like:

-9z^2+24z-32 over C

chimpy400 · « **Reply #1 on:** March 05, 2012, 07:54:13 pm »

$-9z+24z-32$

$= -9(z-\frac{8}{3}z+\frac{32}{9})$

$=-9[(z-\frac{8}{6})^2+\frac{32}{9}-\frac{64}{36})]$

$=-9[(z-\frac{8}{6})^2+\frac{16}{9})]$

$=-9[(z-\frac{8}{6})^2+\frac{-16}{9}i^2)]$

$=-9(z-\frac{8}{6}-\frac{4}{3}i)(z-\frac{8}{6}+\frac{4}{3}i)$

Thats what I got

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Author Topic: Completing the square complex numbers (Read 849 times) Tweet Share

kettles

Completing the square complex numbers

chimpy400

Re: Completing the square complex numbers

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