Random Chem questions.

[oneoneoneone]

Adding a strong base will cause any carboxyl groups ( or any other acidic groups) on the side chains to deprotonate, affecting their capacity for hydrogen bonding as well as making them be attracted to other cationic side chains.
I'm not sure that option 3 will result in denaturation, as if you heated it back up it should still be alright.

I'm pretty sure cooling an enzyme just reduces the rate at which it will bump into the substrate particles, reducing the rate of reaction. Like you said, if you heat the enzyme back up, its tertiary should remain intact, so denaturing only occurs with rises in temperature (and change in pH etc).

[Hutchoo]

Adding a strong base will cause any carboxyl groups ( or any other acidic groups) on the side chains to deprotonate, affecting their capacity for hydrogen bonding as well as making them be attracted to other cationic side chains.
I'm not sure that option 3 will result in denaturation, as if you heated it back up it should still be alright.

I'm pretty sure cooling an enzyme just reduces the rate at which it will bump into the substrate particles, reducing the rate of reaction. Like you said, if you heat the enzyme back up, its tertiary should remain intact, so denaturing only occurs with rises in temperature (and change in pH etc).

Ty man, the first explanation is much better than what the exam provides. It really makes sense haha, very elegant wording btw, tis really nice.

And yeah, i think the tertiary structure does remain the same, but I'm not sure D;;. Hmm, let's wait for someone else to reply and we'll find out.

[Bhootnike]

for vce i think we just need to know that heating a protein can denature it since hydrogen bonding and what not are over come by  heat,
i heard something about how extreme cold can deteriorate(dunno if this implies denaturing) a protein, but i wouldnt dwell on it. im sure its not necessary for us

[oneoneoneone]

I guess if you cooled it down enough it could form extra hydrogen bonds that it shouldn't have  for its optimal usage. I'd just stick with it wouldn't affect the tertiary structure.

[Hutchoo]

This is a basic calculation one, but I forgot how to do them.

How would you convert 1.03  atm into kPa?

[Lasercookie]

This is a basic calculation one, but I forgot how to do them.

How would you convert 1.03  atm into kPa?

1 atm = 101.3 kPa (in the data book)
so: 1.03 atm * 101.3 = 104.3 kPa

To practice, try something like 124 atm to mm Hg, 230 mm Hg to Pascals.

[Hutchoo]

Is this right then 0-o

230 mmHg -> Pascals:

230/760 * 101.3 *1000 = 30365 pascals

124 atm to mmHg
1:760
124: x
simple ratios
124 * 760 = 94240 mmHg.

It's just simple ratios.
Ty for jumpstarting my memory =D

Forgot this stuff was in the databooklet as well!

[Lasercookie]

Yep looks good.

Might want to take another look at the data booklet to make sure you know everything that's in there

[Hutchoo]

Quick yes or no answer/why plz:

ARE ALKENES A FUNCTIONAL GROUP?

[soccerboi]

Apparently they are but i'm not too sure on this one. I saw it on the solutions of one of the exams i did, i think it was sample VCAA 2008.

[oneoneoneone]

I would say they are.

[soccerboi]

Well the definition of a functional group is: A group of atoms responsible for the characteristic reactions of a particular compound.
Does a double bond do this? Yes it does, so therefore it must be a functional group!

[Hutchoo]

Well the definition of a functional group is: A group of atoms responsible for the characteristic reactions of a particular compound.
Does a double bond do this? Yes it does, so therefore it must be a functional group!

LOVE YA MAN

[Reckoner]

Does denaturing just refer to enzymes, or can it be used for proteins in general?

Is a dehydration reaction the loss of water, or the loss of H and O? A practice exam I did explicitly said it was not water, but H and O. Could someone please clarify this?

Also, is the catalyst for the hydrolysis of an ester dilute acid?

Thanks

[charmanderp]

Denaturation refers to enzymes, proteins and DNA and that's it for our course.

Dilute alkali is preferred to dilute acid.