Author Topic: help on differentiate on this question. (Read 732 times) Tweet Share

Zahta · « **on:** June 17, 2012, 03:15:09 pm »

Hey i just dont know where i went wrong in this question. The question Diff e^-4x(xplus 1)

ligands · « **Reply #1 on:** June 17, 2012, 03:25:08 pm »

do you mean $y = e^{-4x}(x+1)?$
in that case it will be just the product rule
$\frac{dy}{dx} = e^{-4x} * \frac{d}{dx}((x+1)) + \frac{d}{dx}(e^{-4x}) * (x+1)$
simply for the answer

Zahta · « **Reply #2 on:** June 17, 2012, 03:33:29 pm »

I did it except the answer has -8 whilst i have -4

b^3 · « **Reply #3 on:** June 17, 2012, 04:05:06 pm »

Quote from: Zahta on June 17, 2012, 03:33:29 pm

I did it except the answer has -8 whilst i have -4

When you took the factor of $\frac{1}{2}$ out, you didn't take the factor out correctly, didn't multiply the -4 by 2.
$(-4x-\frac{7}{2})=\frac{1}{2}(-8x-7)$ not $=\frac{1}{2}(-4x-7)$

Zahta · « **Reply #4 on:** June 17, 2012, 04:20:05 pm »

thankyou so much yeah guys

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Author Topic: help on differentiate on this question. (Read 732 times) Tweet Share

Zahta

help on differentiate on this question.

ligands

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Zahta

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b^3

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Zahta

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